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2 years ago

Julie pays 6.72 for 3.2 pounds of ground beef to make hamburgers. What price per pound does she pay

Mathematics

2 answers:

MrMuchimi2 years ago

8 0

She pays 2.10 for each pound

svetlana [45]2 years ago

4 0

Answer:

6.72/3.2=2.1

Step-by-step explanation:

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What that two numbers when multiplied give 600 and when added give 59

ozzi

Answer:

Step-by-step explanation:

Let the 2 numbers be x and y

From the problem we have that

x * y = 600 and x + y = 59

From x + y = 59 -> x = 59 - y

Plug x = 59 - y to x * y = 600 we have

(59 - y) * y = 600

-> 59y - y^2 = 600

-> -y^2 + 59y - 600 = 0

-> y = $(59 - \sqrt{1081})/2$ or $(59 + \sqrt{1081})/2$

Then we could plug the answers in and find x because x = 59 - y

8 0

2 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

2 years ago

Please help me with this problem! Picture Included!!

alisha [4.7K]

Answer:

y < 1

Step-by-step explanation:

graphing with inequality

6 0

1 year ago

Read 2 more answers

Find the first six terms of the sequence. a1 = 1, an = 4 • an-1

maksim [4K]

$\bf \begin{array}{ccllll}
n&term&value\\
---&-----&-----\\
1&a_1&1\\
2&a_2&4\cdot a_{2-1}\\
&&4\cdot a_1\\
&&4\\
3&a_3&4\cdot a_{3-1}\\
&&4\cdot a_2\\
&&16\\
4&a_4&4\cdot a_{4-1}\\
&&4\cdot a_3\\
&&64\\
5&a_5&4\cdot a_{5-1}\\
&&4\cdot a_4\\
&&256\\
6&a_6&4\cdot a_{6-1}\\
&&4\cdot a_5\\
&&1024
\end{array}$

3 0

2 years ago

Please helppppppp ❤️

liberstina [14]

Answer:

Inverse of f exists.

Step-by-step explanation:

From the graph attached,

If we do the horizontal line test for the function graphed,

We find the function as one to one function.

In other words for every input value (x-value) there is a different output value.

Since, for one-to-one functions, inverse of the functions exist.

Therefore, the answer will be,

The inverse of 'f' exists.

7 0

2 years ago