Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
Answer:
b = 18 units
Step-by-step explanation:
Answer:
The expression for the other number is (n-1)
Step-by-step explanation:
we know that
The difference between two consecutive number is equal to 1
Let
x ----> the smaller of two consecutive number
n ----> the larger of two consecutive numbers
we have that

Solve for x

therefore
The expression for the other number is (n-1)
N= 7.459929 is your answer
Answer:
2
Step-by-step explanation: