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-Dominant- [34]
3 years ago
9

Evaluate the expression 2*2^3*5-3

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
77 would be the answer.
Mumz [18]3 years ago
5 0

Answer:

77 would be the right answer

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Alexus [3.1K]
Multiply the quantity in ounces (including the unit) by the fraction

(1 pint) / (16 fl oz) .
4 0
4 years ago
Can someone help me please​
sashaice [31]

Answer:

7/10

Step-by-step explanation:

I've attached an image on how you can use the diagram they gave you.

If you color in 7/10s and 7/12s you'll notice that 7/10s is greater.

This is because 1/10 of the whole is greater than 1/12 of the whole.

For 1/10, the whole is being divided into 10, so it equals 0.1.

On the other hand, in 1/12, the whole is being divided by 12, so a part equals 0.083

0.1 is greater than 0.083, so 7 of 0.1 is greater than 7 of 0.083

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3 years ago
The lines given by the equations y = 2x and y= 2x + 1 are
Elan Coil [88]
A. is the answer i’m pretty sure
7 0
3 years ago
Please help, much needed. A lot of points
svetoff [14.1K]

Answer:

A. -9

Step-by-step explanation:

If one of the variables were negative than, it would not be able to equal 2/7.

8 0
3 years ago
Read 2 more answers
Lou has an account with $10,000 which pays 6% interest compounded annually. if to that account, lou deposits $5,000 at the begin
Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
3 years ago
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