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2 years ago

N were to share the juice equally, how much would each child get?

Mathematics

1 answer:

marissa [1.9K]2 years ago

6 0

Answer:

You didn't really word your question right, you missed some words

Step-by-step explanation:

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Help please............................

Vesnalui [34]

Step-by-step explanation:

csc x / (cot x + tan x)

Write in terms of sine and cosine.

(1 / sin x) / [(cos x / sin x) + (sin x / cos x)]

Multiply top and bottom by sin x.

1 / [cos x + (sin²x / cos x)]

Multiply top and bottom by cos x.

cos x / (cos²x + sin²x)

Use Pythagorean identity.

cos x / 1

cos x

3 0

3 years ago

A school choir has 36 members. There are three times as many underclassmen as seniors. How many seniors are in the choir?

joja [24]

108 if my maths is correct

5 0

3 years ago

Read 2 more answers

Determine if the following series converges or diverges. Show steps!

MAXImum [283]

Converges by p series test
top section is almost constant, can never be larger than 3
so, compare degrees of their exponents, in this case it’s at a maximum of 3/1000n^2. the same as saying (3/1000)*summation of p series.
converges absolutely.

3 0

3 years ago

Please answer my questions is really easy but idk

GrogVix [38]

Given:

$m \angle A B D=96^{\circ}$

$m \angle 2 =m \angle 1+ 26^{\circ}$

To find:

$m \angle 1$

Solution:

$m \angle DBC+ m \angle CBA = m \angle ABD$

$m \angle 1+ m \angle 2 = m \angle ABD$

Substitute $m \angle 2 =m \angle 1+ 26^{\circ}$ .

$m \angle 1+ m \angle 1 + 26^\circ = 96^\circ$

$2m \angle 1+ 26^\circ = 96^\circ$

Subtract 26° from both sides.

$2m \angle 1+ 26^\circ -26^\circ = 96^\circ -26^\circ$

$2m \angle 1 = 70^\circ$

Divide by 2 on both sides, we get

$m \angle 1=35^{\circ}$

Therefore, m∠1 = 35°.

8 0

3 years ago

Read 2 more answers

Plz Helppp meeee assapppp

Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = $\sqrt{5}$

In a right angle triangle,

$\cos \theta = \dfrac{Base}{Hypotenuse}$

For the given triangle,

$\cos 45^\circ= \dfrac{x}{\sqrt{5}}$

$\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}$

Multiply both sides by $\sqrt{5}$ .

$\dfrac{\sqrt{5}}{\sqrt{2}}= x$

$\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x$

$\dfrac{\sqrt{10}}{2}= x$

Therefore, the required value of x is $\dfrac{\sqrt{10}}{2}$ .

8 0

2 years ago

N were to share the juice equally, how much would each child get? ​

N were to share the juice equally, how much would each child get?