One number is 3 less than 4 times a second number. The difference of the first number and twice the second number is 7. What are
the two numbers?
1 answer:
Answer:
atq= let no.be x and y
x= 4y-3.......(1)
x-2y=7....(2)
subtracting both eqn
x-x+2y=4y-3-7
2y=4y-10
-2y= -10
y=5 ........second no.
first no...x=7+2y=7+10=17.......first no....
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X/8=3
Then multiply both sides by 8
X=24