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Lynna [10]
4 years ago
12

Sin 70°cos 10°-cos 70°sin 10=√3/2

Mathematics
1 answer:
hoa [83]4 years ago
8 0
Let a =70° and b= 10° (and a-b=70-10 =60)
We have the following trigonometric identity:

sin(a-b) = sin(a).cos(b)-sin(b).cos(a) OR:
sin(70-10) = sin70.cos10 - sin10.cos70
But sin(70-10) = sin(60) and we know that sin(60°) =(√3)/2
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Suppose that the functions s and t are defined for all real numbers x as follows.
PolarNik [594]

Answer:

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Step-by-step explanation:

Given the following set of functions

s(x)=2x-2

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(s-t)(x) = s(t) - t(x)

(s-t)(x) = 2x - 2 - 3x

(s-t)(x)  = -x -2

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(s-t)(-1) = -1

(s+t)(x) = s(t) + t(x)

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(s+t)(x)  = 5x -2

(s+t)(-1) = 5(-1) - 2

(s+t)(-1) = -5-2

(s+t)(-1) = -7

8 0
3 years ago
46 cents is what fraction of a dollar
Vikentia [17]
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3 years ago
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What is equivalent fraction to 2/5
My name is Ann [436]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

//  12

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//88

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