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2 years ago

Mark lost 12% of the hockey games he played this year. If Mark lost 6 games, how many total games did he play?

Mathematics

1 answer:

irinina [24]2 years ago

7 0

Answer:

50 games

Step-by-step explanation:

Mark lost 6 games which equals 12% percent of all the hockey games he has played. 6/blank = 12%. 12% equals 0.12. 60 divided by 0.12 equals 50 games.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Probability: $Probability=\frac{favourable\ outcome}{total\ outcome}$

Probability of NOT 6:

$Total\ outcomes=\{1,2,3,4,5,6\}\\\\Number\ of\ total\ outcomes=6\\\\Favourable\ Outcomes= NOT\ 6=\{1,2,3,4,5\}\\\\Number\ of\ favourable\ outcomes=5\\\\P(NOT\ 6)=\frac{5}{6}$

Probability of NOT H:

$Total\ outcomes=\{A,B,C,D,E,F,G,H\}\\\\Number\ of\ total\ outcomes=8\\\\Favourable\ Outcomes= NOT\ H=\{A,B,C,D,E,F,G\}\\\\Number\ of\ favourable\ outcomes=7\\\\P(NOT\ H)=\frac{7}{8}$

Probability of NOT 6 and NOT H:

$Both\ events\ are\ independent\\\\P(NOT\ 6\ and\ NOT\ H)=P(NOT\ 6)\times P(NOT\ H)\\\\P(NOT\ 6\ and\ NOT\ H)=\frac{5}{6}\times \frac{7}{8}\\\\P(NOT\ 6\ and\ NOT\ H)=\frac{35}{48}$

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