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AleksandrR [38]
3 years ago
14

Buddy painted (1/5) of the 320 nutcrackers.How many nutcrackers did buddy paint

Mathematics
2 answers:
maria [59]3 years ago
7 0

Answer: 64

Step-by-step explanation:

just olya [345]3 years ago
3 0

Answer:

64

Step-by-step explanation:

Given that,

Buddy painted (1/5) of the 320 nutcrackers.

We need to find how many nutcrackers did buddy paint. It can be calculated by finding (1/5) of 320.

x=\dfrac{1}{5}\times 320\\\\=64

Hence, he painted 64 nutcrackers.

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The area of a parallelogram is the same as the area of a square. The base of the parallelogram is twice the length of its height
Allisa [31]

Answer:

(B)

The areas of the square and parallelogram are equal

5 0
3 years ago
Read 2 more answers
Point S has the coordinates (6,-4).​
BabaBlast [244]
Point S (6,-4)

Point T

(6 x -1, -4) = (-6, -4)

Point T = (-6,-4)

Point T shows the reflection of Point S across the y axis.

Hope this helps :)
P.S please give me brainlest
7 0
3 years ago
Determine the value of X<br><br> AB is the mid segment of triangle LMN. Determine the value of X
r-ruslan [8.4K]

Answer:

<h2>B.  4</h2>

Step-by-step explanation:

Since ,AB is the mid segment of triangle LMN

Then

\Longleftrightarrow AB=\frac{MN}{2}

\Longleftrightarrow x+8=\frac{5x+4}{2}

\Longleftrightarrow 2\times(x+8)=5x+4

\Longleftrightarrow 2x+16=5x+4

\Longleftrightarrow 16-4=5x-2x

\Longleftrightarrow 3x=12

\Longleftrightarrow x=\frac{12}{3}=4

7 0
2 years ago
A faucet is leaking at a rate of 4.2 milliliter per minute. How many gallons of water does the faucet leak per day? Use 1 L = 0.
pentagon [3]

Answer:

1.57 gallons of water to the nearest hundredth.

Step-by-step explanation:

The number of minutes in a day = 24*60 minutes.

1 L = 0.26 gal

So 4.2 milliliters =   0.26 * 4.2 / 1000 gals.

So the number of gallons leaked in a day

= 24* 60 * (0.26*4.2) / 1000

= 1.572 gals.

3 0
3 years ago
The answer please. (F-g)(-3)
ad-work [718]
There are two ways to do this
Method 1:

Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1

Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38

-----------------------------------------

Method 2:

Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48

Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10

Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38

-----------------------------------------

Whichever method you pick, the answer is: 38

4 0
3 years ago
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