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Elan Coil [88]
3 years ago
11

Inequality in real world.

Mathematics
1 answer:
Oxana [17]3 years ago
3 0
Solving real-world problems that involve inequalities is very much like solving problems that involve equations.

Example 1

In order to get a bonus this month, Leon must sell at least 120 newspaper subscriptions. He sold 85 subscriptions in the first three weeks of the month. How many subscriptions must Leon sell in the last week of the month?

Solution

Let x = the number of subscriptions Leon sells in the last week of the month. The total number of subscriptions for the month must be greater than 120, so we write :

85 + x ≥ 120.

We solve the inequality by subtracting 85 from both sides: x ≥ 35.

Leon must sell 35 or more subscriptions in the last week to get his bonus.

Check

To check the answer, we see that 85 + 35 = 120. If he sells 35 or more subscriptions, the total number of subscriptions he sells that month will be 120 or more. The answer checks out.

Example 2

Virenas Scout troop is trying to raise at least $650 this spring. How many boxes of cookies must they sell at $4.50 per box in order to reach their goal?

Solution

Let x = number of boxes sold. Then the inequality describing this problem is 4.50 ≥ 650.

We solve the inequality by dividing both sides by 4.50: x ≥ 144.44.

We round up the answer to 145 since only whole boxes can be sold.

Virenas troop must sell at least 145 boxes.

Check

If we multiply 145 by $4.50 we obtain $652.50, so if Virenas troop sells more than 145 boxes they will raise more than $650. But if they sell 144 boxes, they will only raise $648,

which is not enough. So they must indeed sell at least 145 boxes. The answer checks out.

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the combined area of two squares is 45 square cm. Each side of one square is twice as long as the side of the other Square. What
Vlad1618 [11]

Answer:

L=6 cm l=3

Step-by-step explanation:

x+y=45


L=2l


Big Square Area


L*L=x


Little Square

l*l=y



Substituting

(L*L)+(l*l)=45

(2l*2l)+(l*l)=45

(4l^2)+(l^2)=45

5l^2=45

l^2=45/5

l^2=9

l=sqrt(9)

l=3

L=2(3)

L=6


4 0
3 years ago
There is 1500 ft of fencing available to make 6 identical pens. Find the maximum area for EACH pen (meaning maximum of one pen).
hjlf

Answer:

The maximum area is therefore is 93750 ft²

Step-by-step explanation:

The given parameter are;

The a]length of fencing available = 1500 ft.

The perimeter of the figure = 9·x + 4·y

Therefore, 9·x + 4·y = 1500 ft.

The area of the figure = 6 × (x × y) = 3·x × 2·y

From the equation for the perimeter, we have;

9·x + 4·y = 1500

y = 1500/4 - 9/4·x = 375 - 9/4·x

y = 375 - 9/4·x

Substituting the value of y in the equation for the area gives;

Area = 3·x × 2·y = 3·x × 2·(375 - 9/4·x) = 2250·x - 27/2·x²

Area = 2250·x - 27/2·x²

The maximum area is found by taking the derivative and equating to zero as follows;

d(2250·x - 27/2·x²)/dx = 0

2250 - 27·x = 0

x = 2250/27 = 250/3

x = 250/3

y = 375 - 9/4·x = 375 - 9/4×250/3 = 187.5

The maximum area is therefore, 3·x × 2·y = 3 × 250/3 × 2 × 187.5 = 93750 ft²

The maximum area is therefore = 93750 ft.²

4 0
3 years ago
Simplify: Square root of 8xy squared
SashulF [63]

Answer:

8xy

Step-by-step explanation:

\sqrt{(8xy)^{2}}=\sqrt{(8)^{2}x^{2}y^{2}} =8xy

6 0
4 years ago
Match the numerical expressions to their simplest forms
zimovet [89]

I hope you did well on this question.

6 0
3 years ago
Mr. and Mrs. Suralbo earned a net taxable income of P568,986. Find the income tax due.
Contact [7]

Answer:

$198,000

Step-by-step explanation:

Since Mr. and Mrs. Suralbo are married and filing jointly, they would fall into the tax slab of 35% as their taxable income ranges between $414,701 to $622,050.

Taxable income = $568,986

Tax rate = 35%

Income tax due = $568,000 * 35/100

= $198,000

Thus, the income tax due for Mr. and Mrs. Suralbo would be $198,000.

8 0
3 years ago
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