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Elan Coil [88]
3 years ago
11

Inequality in real world.

Mathematics
1 answer:
Oxana [17]3 years ago
3 0
Solving real-world problems that involve inequalities is very much like solving problems that involve equations.

Example 1

In order to get a bonus this month, Leon must sell at least 120 newspaper subscriptions. He sold 85 subscriptions in the first three weeks of the month. How many subscriptions must Leon sell in the last week of the month?

Solution

Let x = the number of subscriptions Leon sells in the last week of the month. The total number of subscriptions for the month must be greater than 120, so we write :

85 + x ≥ 120.

We solve the inequality by subtracting 85 from both sides: x ≥ 35.

Leon must sell 35 or more subscriptions in the last week to get his bonus.

Check

To check the answer, we see that 85 + 35 = 120. If he sells 35 or more subscriptions, the total number of subscriptions he sells that month will be 120 or more. The answer checks out.

Example 2

Virenas Scout troop is trying to raise at least $650 this spring. How many boxes of cookies must they sell at $4.50 per box in order to reach their goal?

Solution

Let x = number of boxes sold. Then the inequality describing this problem is 4.50 ≥ 650.

We solve the inequality by dividing both sides by 4.50: x ≥ 144.44.

We round up the answer to 145 since only whole boxes can be sold.

Virenas troop must sell at least 145 boxes.

Check

If we multiply 145 by $4.50 we obtain $652.50, so if Virenas troop sells more than 145 boxes they will raise more than $650. But if they sell 144 boxes, they will only raise $648,

which is not enough. So they must indeed sell at least 145 boxes. The answer checks out.

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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
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Your Nana gives you $50 for making all A’s/B’s on your last report card. You have been eying a new pair of Crocs + their fancy c
satela [25.4K]

Answer:

Yes you have enough money because with the dicound the crocs are $45.50

Step-by-step explanation:

u have $50 the crocs is $65 but have 30% off

$65 with 30% off is $45.50

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2 years ago
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seropon [69]

Answer:

9 and 11

Step-by-step explanation:

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3 years ago
3x - 3y = 9 and x + 3y = 12 <br> Elimination
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Answer:

x=5.25,y=2.25

Step-by-step explanation:

We can add the two equations to eliminate the variable y and solve for x:

3x-3y+x+3y=9+12

4x=21

x=5.25

Now, we can use substitution to solve for y:

x+3y=12 (given)

5.25+3y=12

3y=12-5.25

=6.75

y=2.25

Hope this helps :)

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Solve the system of equations algebraically. Show all of your work.<br> y= x^2 + 2x<br> y= 3x +30
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Answer:

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