Answer:
<u>The solutions to this quadratic equation are 10 and 3.</u>
Step-by-step explanation:
1. Let's recall the formula for solving this type of equations, called quadratic equations:
x = ( - b +/- √ b² - 4ac)/ 2a
The equation given is x2 – 13x + 30 = 0,
where a = 1, b = - 13 and c = 30
Now replacing with the real values, we have
x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1
x = [ 13 +/- √ 169 - 120] / 2
x = [13 +/- √ 49]/ 2
x = [ 13 +/- 7 ]/ 2
<u>x₁ = 13 + 7/2 = 20/2 = 10</u>
<u>x₂ = 13 - 7/2 = 6/2 = 3</u>
All of the angles should be the same because a square has all equal angles and side lengths.
Answer:
x=-4 and y=10
Step-by-step explanation:
Use the second equation to make y=x+6
sub y=x+6 into the first equation
-x-2*(x+6)=0
-x-2x-12=0
-3x-12=0
3x=-12
x=-4
Now sub x=-4 into the second equation
-(-4)+y=6
y=6+4
y=10
Answer:
I'm not sure the answer to this
