Determine the points for the graph of the relation y = -5x -3 using the x-values given in the table
1 answer:
You might be interested in
We use trigonometry because we know an angle and a side length.
We are looking for one of the sides that isn't the hypotenuse:
As illustrated by the picture I made below:
We know both unknown angles will be 45 degrees, as there are 180 degrees in a triangle, we know the triangle is a right angle triangle (has 90 degrees) so, (180-90)/2 = 45
Using SOH CAH TOA, short for : SIN- OH COS- AH TAN- OA
We are looking for the one with H, as we know what H is.
I am picking "SIN- OH", but we could use "COS- AH"
The formula for this is: Sin(angle) = O/H
<u /><u>We substitute the angle (45) and the length for H (16)
</u>
Sin(45)= O/16 <- rearrange it
Sin(45)*16= O <- Solve in the calculator
13.6145 (4 DP)= O
The legs = O
The legs have a length of "13.6145 (4 DP)" each
We are looking for one of the sides that isn't the hypotenuse:
As illustrated by the picture I made below:
We know both unknown angles will be 45 degrees, as there are 180 degrees in a triangle, we know the triangle is a right angle triangle (has 90 degrees) so, (180-90)/2 = 45
Using SOH CAH TOA, short for : SIN- OH COS- AH TAN- OA
We are looking for the one with H, as we know what H is.
I am picking "SIN- OH", but we could use "COS- AH"
The formula for this is: Sin(angle) = O/H
<u /><u>We substitute the angle (45) and the length for H (16)
</u>
Sin(45)= O/16 <- rearrange it
Sin(45)*16= O <- Solve in the calculator
13.6145 (4 DP)= O
The legs = O
The legs have a length of "13.6145 (4 DP)" each
That line is in point-slope form:
Where 'm' is the slope and (x1, y1) is a point on the line.
Perpendicular lines have opposite slopes. To get the opposite, we take the reciprocal and multiply it by -1.
Reciprocal:
Multiply by -1:
We can plug this slope and the point into point-slope form, and then convert it to slope-intercept form.
Negatives cancel out:
Distribute 1 into the parenthesis:
Subtract 2 to both sides:
Where 'm' is the slope and (x1, y1) is a point on the line.
Perpendicular lines have opposite slopes. To get the opposite, we take the reciprocal and multiply it by -1.
Reciprocal:
Multiply by -1:
We can plug this slope and the point into point-slope form, and then convert it to slope-intercept form.
Negatives cancel out:
Distribute 1 into the parenthesis:
Subtract 2 to both sides: