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valentina_108 [34]
3 years ago
5

Determine the points for the graph of the relation y = -5x -3 using the x-values given in the table

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

A. Yes. Each x value has only one y value. No x value has 2 different y values.

B. For the table, y is 8 when x is 11.

Plug in the value to determine the y value for the equation.

f(x)= 5(11)-21

f(x)= 55-21

f(x)= 34

Since 34>8, the value of the equation f(x) is greater when x=11.

C. 99=5x-21

120=5x

x=24

Final answer: 24

Step-by-step explanation:

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PLS HELP DUE IN 1 HOUR WILL GIVE BRAINLIEST 5 STARS AND A THANKSSSS !
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Answer:

15

Step-by-step explanation:

33=9.8x-7.6x

33=2.2x

33/2.2=x

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4 0
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Plz help i will give 20 points just plz help
Rus_ich [418]

Answer:

36

Step-by-step explanation:

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Can you solve for y plz
vredina [299]
Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
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3 years ago
The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b
ANEK [815]

Answer:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

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Answer:

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Step-by-step explanation:

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