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Verizon [17]
3 years ago
11

Consider the differential equation y prime left parenthesis t right parenthesisequalst squared minus 6 y squared and the solutio

n curve that passes through the point ​(3​,1​). What is the slope of the curve at ​(3​,1​)?
Mathematics
1 answer:
White raven [17]3 years ago
6 0

Answer:

The slope of the curve at ​(3​,1​) is 3.

Step-by-step explanation:

The given differential equation is

y'(t)=t^2-6y^2

It is given that the solution curve is passing through the point ​(3​,1​).

The slope of a curve y(t) at a point (a,b) is the value of y'(t) at (a,b).

We need to find the slope of the curve at ​(3​,1​).

m=[y'(t)]_{(3,1)}

m=[t^2-6y^2]_{(3,1)}

Substitute t=3 and y=1 in the above equation, to find the slope.

m=(3)^2-6(1)^2

m=9-6

m=3

Therefore the slope of the curve at ​(3​,1​) is 3.

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