What does it mean when the point on a number line is open?

The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x) = x^2, which of

katrin [286]

The transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The options are missing.

The options are:

A. G(x) = 4x²

B. G(x) = -(1/4)x²

C. G(x) = -4x²

D. G(x) = (1/4)x²

We have an equation of a function F(x)

F(x) = x²

The transformation F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x)

To stretch vertically if the function is multiplied by a constant value

f(x) = ax²

To flip over the x-axis if multiply by negative value.

g(x) = -ax²

From the options

G(x) = -4x²

Thus, the transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

Learn more about the function here:

brainly.com/question/5245372

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6 0

1 year ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

Mr Nelson paid $3.84 tax he pay the sales tax rate of 8% how much was item he was buying before sales tax was added

UkoKoshka [18]

Answer:

Mr. Nelson paid $48 befor tax.

Step-by-step explanation:

Let x be the price of the item before tax.

108 % * x - x = 3.84 (the tax itself)

27/25x - x = 3.84

2/25 x = 3.84

x = 48

3 0

2 years ago

Which one of these show the multiplication property of equality? I know what is it I just don’t see it on here, 5 and 9 both loo

Fofino [41]

Answer:

5 is c 9 is f

8 0

3 years ago

(3 points)

Snezhnost [94]

Answer:

The exponential Function is $20+12h=200$ .

Farmer will have 200 sheep after <u>15 years</u>.

Step-by-step explanation:

Given:

Number of sheep bought = 20

Annual Rate of increase in sheep = 60%

We need to find that after how many years the farmer will have 200 sheep.

Let the number of years be 'h'

First we will find the Number of sheep increase in 1 year.

Number of sheep increase in 1 year is equal to Annual Rate of increase in sheep multiplied by Number of sheep bought and then divide by 100.

framing in equation form we get;

Number of sheep increase in 1 year = $\frac{60}{100}\times20 = 12$

Now we know that the number of years farmer will have 200 sheep can be calculated by Number of sheep bought plus Number of sheep increase in 1 year multiplied by number of years is equal to 200.

Framing in equation form we get;

$20+12h=200$

The exponential Function is $20+12h=200$ .

Subtracting both side by 20 using subtraction property we get;

$20+12h-20=200-20\\\\12h=180$

Now Dividing both side by 12 using Division property we get;

$\frac{12h}{12} = \frac{180}{12}\\\\h =15$

Hence Farmer will have 200 sheep after <u>15 years</u>.

6 0

3 years ago