To find the roots of the quadratic equation x^2 + 2x + 5 = 0 is the same as solving it for x.
The formula to get x₁ and x₂ is: x₁,x₂=(-b⁺/₋√(b²-4ac))/(2a) where in our case a=1, b=2 and c=5.
Lets input the numbers:
x₁,x₂= (-2⁺/₋√(2²-4*1*5))/(2*1) = (-2⁺/₋√(4-20))/2, = (-2⁺/₋√(-16))/2
We see that we have a minus sign under the square root so the solutions or roots for our quadratic equation are going to be complex numbers:
x₁ = (-2+4i)/2 = -1+2i
x₂ = (-2-4i)/2 = -1-2i
So our roots are complex and are: x₁= -1+2i and x₂= -1-2i.
Answer:
± 3
Step-by-step explanation:
let n be the number then the number squared is n² , so
6n² = 54 ( divide both sides by 6 )
n² = 9 ( take the square root of both sides )
n = ± = ± 3
That is the number is 3 or - 3
There are possible outcomes. At the least, you can draw (1, 2, 3) to get a sum of 6, and at most (5, 6, 7) for a sum of 18. Then the PMF is
That is, consider all the possible sums and their integer partitions. For example,
6 = 1 + 2 + 3
7 = 1 + 2 + 4
8 = 1 + 2 + 5 = 1 + 3 + 4
9 = 1 + 2 + 6 = 1 + 3 + 5 = 2 + 3 + 4
and so on.
Then the expected value is
We can find the variance via
Answer:
2/8
Step-by-step explanation:
If this is the case, then you know by the polynomial remainder theorem that
is a factor of
, so there is some polynomial
such that