Let;
A(-8,6) B(6,6) C(6, -4) D(-8, -4)
Let's find the length AB
x₁= -8 y₁=6 x₂=6 y₂=6
We will use the distance formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![=\sqrt[]{(6+8)^2+(6-6)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%286%2B8%29%5E2%2B%286-6%29%5E2%7D)
![=\sqrt[]{14^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%2B0%7D)
Next, we will find the width BC
B(6,6) C(6, -4)
x₁= 6 y₁=6 x₂=6 y₂=-4
substitute into the distance formula;
![d=\sqrt[]{(6-6)^2+(-4-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%286-6%29%5E2%2B%28-4-6%29%5E2%7D)
![=\sqrt[]{(-10)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-10%29%5E2%7D)
![=\sqrt[]{100}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B100%7D)
Area = l x w
= 14 x 10
= 140 square units
Answer:
6 divided by 3/5 is 10
Step-by-step explanation:
I don't know how to do the number line, sorry.
Which of these is equal to cos 47°?
a. cos 43°
b. sin 43°
c. tan 43°
d. cos 133°
B.....
cos (47°)= sin (90°-47°)=sin (43°) [complementary angles]
Answer B
Answer:
6/7
Step-by-step explanation:
45x+34=24x+16
collect like terms, we now have;
45x-24x=16-34
21x=-18
X=18/21
X=6/7
<span>Use the formula d=sqrt[(x₂-x₁)^2+(y₂-y₁)^2] to find distance between 2 points.
DE = </span><span>√17
EF = </span><span>√18
FD = </span><span>√17
See the attachment for the complete workout.
Since,All the sides are not same to make an equilateral triangle.
So its not an equilateral triangle</span>
