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VashaNatasha [74]

3 years ago

15

Suppose that X has the normal distribution for which the mean is 1 and the variance is 4. Find the value of each of the followin

g probabilities:
a. Pr(X ≤ 3)
b. Pr(X > 1.5)
c. Pr(X = 1)
d. Pr(25)
e. Pr(X ≥ 0)
f. Pr(−10.5)
g. Pr(|X| ≤ 2)
h. Pr(1≤−2X + 3 ≤ 8)

1 answer:

daser333 [38]3 years ago

8 0

The answer is b hope this helps

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1 year ago

The difference of x and 18 is greater than or equal to -12<br><br>its a inequality question

slavikrds [6]

Writing the word problem as an equation you get:

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2 years ago

8 × 10 + 6 − 2 7 + 5 × 8 − 4

riadik2000 [5.3K]

Answer:

95

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

Find the circumference of a circle with an area of 615.75 square inches.

Fittoniya [83]

A=pie×radius squared is the area formula of a circle. The circumference formula or a circle is C=pie×diameter. 615.75=(3.14)(radius) squared. Divide both sides by the 3.14. What ever 615.75 divided by 3.14 is-is radius squared. The square root is your radius. The radius is half the diameter, so double what you have right now as the radius to get the diameter. Now since C=pie×diameter, your circumference is your pie×your diameter. Whatever your answer is-is your circumference.

3 0

3 years ago

Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv

uysha [10]

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(more than 4.25 minutes to solve a problem)

$P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%$

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

8 0

2 years ago