You can find the answer yourself. It is not that hard, just talk to your teacher.
Answer:
C
Step-by-step explanation:
The graph shows it clearly.
The last choice, f(x)=1/4(4ˣ⁻⁻¹)-4, is correct.
Substituting our values for x, we have:
f(2) = 1/4(4²⁻¹)-4 = 1/4(4¹) - 4 = 1/4(4) - 4= 1 - 4 = -3
f(3) = 1/4(4³⁻¹)-4 = 1/4(4²) - 4 = 1/4(16) - 4 = 4 - 4 = 0
f(4) = 1/4(4⁴⁻¹)-4 = 1/4(4³) - 4 = 1/4(64) - 4 = 16 - 4 = 12
All of the data points fit.
A.) Probability of selecting two students and two faculty members from 20 students and 5 faculty volunteers = no of ways of selecting two students and two faculty members from 20 students and 5 faculty volunteers divided by the number of ways of selecting 4 people from 25 people = (20C2 x 5C2) / 25C5 = 1900 / 53130 = 0.036 = 3.58%
b.) Probability of selecting three students and one faculty members from 20
students and 5 faculty volunteers = no of ways of selecting three students
and one faculty members from 20 students and 5 faculty volunteers
divided by the number of ways of selecting 4 people from 25 people = (20C3 x 5C1) / 25C5 = 5700 / 53130 = 0.107 = 10.7%
<span>This equation have one solution.
</span><span>
5(2x – 3) = 5
2x - 3 = 5/5
2x - 3 = 1
2x = 1 + 3
2x = 4
x = 4/2
x = 2
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