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Paladinen [302]
4 years ago
15

24 students in a class took an algebra test.

Mathematics
1 answer:
Shkiper50 [21]4 years ago
6 0
The answer to this question is 75%
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In a class of 34 students, 19 of them are girls.
cluponka [151]

Answer:

55.8

Step-by-step explanation:

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3 years ago
If you have a population standard deviation of 9 and a sample size of 144, what is your standard error of the mean?
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So your answer would be 1296
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Yair is buying a dog carrier for his puppy. The carrier is 20 inches long, 13 inches wide, and 16 inches high. What is the volum
scZoUnD [109]

Answer:

4160 cubic inches

Step-by-step explanation:

The dog carrier is in the shape of a rectangular prism (cuboid).

The volume of a rectangular prism is given as:

V = L * W * H

where L = length, W = width, H = height

The carrier is 20 inches long, 13 inches wide, and 16 inches high.

Therefore, its volume is:

V = 20 * 13 * 16\\V = 4160 in^3

The volume of the dog carrier is 4160 cubic inches.

4 0
4 years ago
PLEAS HELP ME QUICK I WILL GIVE BRAINLY
Anna007 [38]

Answer:

length of rectangle(l)=x

breadth(b)=5

perimeter of rectangle=2(l+b)=2(X+5)=2X+10

area if rectangle= l×b=X×5=5x.

plz give me brainliest

5 0
3 years ago
Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = −sin x, [0,
deff fn [24]

Answer with Step-by-step explanation:

We are given that

f(x)=-sin x

[0,\infty]]

Average value of the function is given gy

f_{avg}=\frac{1}{b-a}\int_{a}^{b}f(x)dx=\frac{1}{\pi-0}\int_{0}^{\pi}-sinx dx

f_{avg}=\frac{1}{\pi}[cosx]^{\pi}_{0}

Using the formula

\int sin xdx=-cos x

f_{avg}=\frac{1}{\pi}(cos\pi-cos0)

f_{avg}=\frac{1}{\pi}(-1-1)=-\frac{2}{\pi}

f(x)=f_{avg}

-sinx=-\frac{2}{\pi}

sinx=\frac{2}{\pi}

x=sin^{-1}(\frac{2}{\pi})=0.69radian

7 0
3 years ago
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