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3 years ago

14

If a determinant of a 2 x 2 matrix is 0, what can you conclude about the inverse of the matrix?

1 answer:

icang [17]3 years ago

3 0

Any singular matrix (a matrix with zero determinant) has no inverse.

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

I need help ASAP!!Please explain how to solve the problem

rjkz [21]

Answer:

( x - 2 )^2 + ( y - 1 )^2 = 1

Step-by-step explanation:

As i previously explained,

The general form of equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2.

h and k are the co-ordinates of the center of circle and r is the radius

Here, We have (2,1) as the co-ordinates of the center of circle

Now,

( x - h )^2 + ( y - k )^2 = r^2

or,( x - 2 )^2 + ( y - 1 )^2 = r^2

The radius of the circle is 1 units(from figure)

So, put that in, we get

( x - 2 )^2 + ( y - 1 )^2 = 1^2

or, ( x - 2 )^2 + ( y - 1 )^2 = 1

You can simplify this or leave it here.

8 0

3 years ago

What is <br> the equation of the line that passes through the points (-6,6) and (-1,-9)

IgorLugansk [536]

Answer:

The answer to the question provided is y = -3x - 12.

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

$y = mx + b$

❃Incase you also forgot, what the slope formula is ☟

$m = \frac{y_2 - y_1 }{x_2 - x_1}$

➊ First: We are going to be solving for the slope.

$m = \frac{ - 9 - 6}{ - 1 - ( - 6)} = \frac{ - 15}{ \: \: \: 5} = - 3$

➋Second: We find the y-intercept.

$y = mx + b \\ 6 = - 3( - 6) + b \\ 6 = 18 + b \\ \frac{ - 18 = - 18 \: \: \: \: \: \: \: \: \: \: \: \: }{ - 12 = b}$

➌Third: Plug in.

$y = - 3x - 12$

6 0

3 years ago

What is the sum?<br> 8+(-12)<br> О-20<br> 0-4<br> 020

rodikova [14]

Answer: -4

Work: So, to get -4, we need to simplify the equation. If you see any equation with +(- that's subtraction. So, with the rule, this equation is basically 8-12, and that's -4.

7 0

3 years ago

Read 2 more answers

On a journey of 120 km, a motorist averages

fenix001 [56]

Answer:

More

Step-by-step explanation:

Because the journey is 120km long, and the mortoristgoes less than 60km per hour. So in 2 hours, the motorist will go less than 120 km. So he needs more than 2 hours to go 120 km

8 0

3 years ago

Read 2 more answers