Answer:
the answer to your question is 8r(d-3)
hope this helps :-)
Answer:
mmmmmm it would be 50 but if thats not a awnser on the thingy just pick 51
Step-by-step explanation:
The number of weeks required to have enough money in account to buy computer is 12
<em><u>Solution:</u></em>
Given that Maya has $210 in a savings account for a new computer the computer cost $537.15 including sales tax
At the end of each week she deposits $27 into the account
<em><u>To find: number of weeks required to have enough money in the account for the computer</u></em>
Total cost of computer = $ 537.15
Amount in savings account = $ 210
Let "a" be the number of weeks required to have enough money in account to buy computer
Each week she deposits $27 into the account
<em><u>So we can we frame a equation as:</u></em>
total cost of computer = Amount in savings account + (number of weeks x 27)
Thus number of weeks required is 12 approximately
Answer:
A)
Decay
B)
Initial value is 5.
C)
The decay factor is 0.75.
D)
75%
Step-by-step explanation:
An exponential function is given by:
Where a is the initial value and r is the rate.
We have the function:
So, a = 5 and r = 1/4.
A)
Remember the guidelines:
- It is exponential growth if r > 1.
- And it is exponential decay if r < 1. (And r must be positive.)
Our rate is 1/4 or 0.25.
It is less than 1, so our function is exponential decay.
B)
The initial value is the value in front of our rate.
So, our initial value in this case is 5.
C)
The decay factor will be 1 - r, where r is our rate.
Since our rate is 0.25, our decay factor is 1 - 0.25 = 0.75.
So, we are decaying by a factor of 0.75.
D)
To convert a decimal to a percent, we move the decimal dot two places to the rght and add a percent sign.
So, 0.75 will be 75.0 % or smply 75%.
It is a 75% decay.
Answer:
El monto que pagará Jorge por la compra de 5 kilogramos de arroz y 13 kilogramos de azúcar es de S/53.7
Step-by-step explanation:
Denominemos un kilogramo de arroz como R y un kilogramo de azúcar como A, por lo tanto tenemos;
8 · R + 10 · A = 60 .............................. (1)
20 · R + 15 · A = 126 .......................... (2)
Multiplicando la ecuación (1) por 1.5 y restando el resultado de la ecuación (2), tenemos;
20 · R + 15 · A - 1.5 × (8 · R + 10 · A) = 126 - 1.5 × 60 = 36
8 · R = 36
R = 36/8 = S/4.5
Lo que da, de la ecuación (1);
8 · R + 10 · A = 60 = 8 × 4.5 + 10 · A = 60.
10 · A = 60 - 8 × 4.5 = 24
A = 24/10 = 2.4 = S/2.4
Por lo tanto, 5 kilogramos de arroz y 13 kilogramos de azúcar costarán
5 × 4.5 + 13 × 2.4 = S / 53.7.
El monto que Jorge pagará por la compra de 5 kilogramos de arroz y 13 kilogramos de azúcar = S/53.7.