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anastassius [24]
3 years ago
10

25xy=225 convert to polar form

Mathematics
1 answer:
bixtya [17]3 years ago
6 0
\bf x=rcos(\theta)\qquad \qquad y=rsin(\theta)\\\\
-----------------------------\\\\
25xy=225\implies xy=\cfrac{225}{25}\implies xy=9
\\\\\\
rcos(\theta)\cdot rsin(\theta)=9\impliedby \textit{common factor}
\\\\\\
r[cos(\theta)sin(\theta)]=9\implies r=\cfrac{9}{cos(\theta)sin(\theta)}
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A parachutist's speed during a free fall reaches 50 meters per second. What is this speed in feet per second? At this speed, how
BigorU [14]

50m ≅164 ft (3s.f.)

50m/s≅164 ft/s

distance after 20s:

d=164 ft/s ⋅20s

=3280ft

Hope This Helps!

7 0
1 year ago
Correct I’ll give brainlist no links or I’ll report
padilas [110]

Answer:

None of these answers

Step-by-step explanation:

Plug the points into the equation to see if they make sense

(4,-10),  -10=3(4)+2, -10=12+2, -10=14. Incorrect

(10,-4). -4=3(10)+2, -4=30+2, -4=32. Incorrect

(-10,-4), -4=3(-10)+2, -4=-30+2, -4=-28. Incorrect

Therefore, the answer is none of these answers

If this helps please mark as brainliest

5 0
2 years ago
Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3
gayaneshka [121]

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0
2 years ago
Out of these numbers which two are perfect squares. 20.25, 32, 16.9, 3.24
a_sh-v [17]

Answer:

<h2><em><u>3.24</u></em> </h2>

<em><u>= yes, because the sqrt of 3.24 is 1.8</u></em>

<h2><em><u>20.25</u></em></h2><h3>= yes, because the sqrt of 20.25 is 4.5</h3>
5 0
3 years ago
Simplify. 5x^3/(7x^3+x^4)
Mashutka [201]
Hello,

\frac{5 x^{3} }{7 x^{3} + x^{4} } = \frac{5 x^{3} }{x^{3}(7+x) }=\frac{5} {7+x}

Answer Almost A with parenthesis 

5/(7+x)


6 0
3 years ago
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