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pshichka [43]
3 years ago
7

Jesse takes his dog and cat for their annual vet visit. Jesse's dog weighs 23 pounds. The vet tells him his cats weight is 5/8 a

s his dogs weight. How much does his cat weigh?
Mathematics
1 answer:
Anton [14]3 years ago
8 0
Dog weigh: 23
cat weigh: 5/8 dogs weigh 
so.. 
23x5/8 = 115/8  
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Write an inequality that represents the following scenario: a number divided by 10 increased by 8 is greater than 15.
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3 years ago
The marketing club at school is opening a student store. They randomly survey 50 students about how much money they spend on lun
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Answer:

The expected value for a student to spend on lunch each day = $5.18

Step-by-step explanation:

Given the data:

Number of students______$ spent

2 students______________$10

1 student________________$8

12 students______________$6

23 students______________$5

8 students_______________$4

4 students_______________$3

Sample size, n = 50.

Let's first find the value on each amount spent with the formula:

\frac{num. of students}{sample size} * dollar spent

Therefore,

For $10:

\frac{2}{50} * 10 = 0.4

For $8:

\frac{1}{50} * 8 = 0.16 l

For $6:

\frac{12}{50} * 6 = 1.44

For $5:

\frac{23}{50} * 5 = 2.3

For $4:

\frac{8}{50} * 4 = 0.64

For $3:

\frac{4}{50} * 3 = 0.24

To find the expected value a student spends on lunch each day, let's add all the values together.

Expected value =

$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24

= $5.18

Therefore, the expected value for a student to spend on lunch each day is $5.18

7 0
2 years ago
How does a reflection across the y-axis change the coordinates of a shape?
Dmitriy789 [7]

Answer:

in (x,y), it becomes (-x,y)

Step-by-step explanation:

8 0
3 years ago
What is 1/6d+2/3 = 1/4(d-2)
GenaCL600 [577]
1/6d + 2/3 = 1/4(d - 2)

First, simplify \frac{1}{6} d to \frac{d}{6} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{1}{4} (d - 2)
Second, simplify \frac{1}{4} (d - 2) to \frac{d-2}{4} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{d-2}{4}
Third, multiply both sides by 12 (the LCM of 6,4) / Your problem should look like: 2d + 8 = 3(d - 2)
Fourth, expand. / Your problem should look like: 2d + 8 = 3d - 6
Fifth, subtract 2d from both sides. / Your problem should look like: 8 = 3d - 6 - 2d
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Answer:

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7 0
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