f(x)=2x^2+0x-5
Find the vertex
0/4=0=x
Input x into the equation to find y or f(x)
0+0-5=f(x)
(0,-5) = Vertex
Now find a random x coordinate to input into the equation.
Let's do 4.
32+0-5=f(x)=27
It may not look like a parabola due to it being uneven.
The answer would be 3, 2-2+3, I’m pretty sure.
To find this out multiply 2 * 2 * 2 * 2 to get 16 possible combinations
10×5 is the answer. not sure though