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Mrac [35]
3 years ago
10

Suppose a college surveyed its students and found that two-thirds of them sleep at least seven hours each night. on a campus of

918 students, how many students could be expected to sleep at least seven hours each night?
Mathematics
1 answer:
Rus_ich [418]3 years ago
4 0
The answer is <span>606 students.

2/3 is equivalent to 0.66

You multiply 918 and 0.66

918 x 0.66 = </span><span>605.88.

</span><span>You round 605.88 to the nearest whole which is 606 students.</span>
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Write the equation of the line graphed below in Point-Slope form. Use the point labeled on the graph. State the slope and point.
saw5 [17]

Given:

The graph of a line.

To find:

The point-slope form of the given line.

Solution:

From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-1-5}{0-1}

m=\dfrac{-6}{-1}

m=6

The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:

y-y_1=m(x-x_1)

y-5=6(x-1)

Therefore, the point-slope form is y-5=6(x-1), slope is 6 and the point is (1,5).

6 0
3 years ago
Petes dog weighed 30 pounds it then lost 16% of it's weight how much did pete lose
Paraphin [41]

Answer:

4.8 pounds!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


6 0
3 years ago
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(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Consider the table of the powers of 8.
allsm [11]
A= 0
B= -8
C= -64

I learned how to do math and that is correct
6 0
3 years ago
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Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

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Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
3 years ago
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