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Reil [10]
3 years ago
12

does anybody know this ???

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

(a) angle ACB is not proper way

masya89 [10]3 years ago
5 0

Answer:

A.

Step-by-step explanation:

We can read the angle with the labels found in answers B, C and D.

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Does anyone know how to do this?
nekit [7.7K]
That look hard what subject is it
7 0
3 years ago
Read 2 more answers
A survey was conducted that asked 1003 1003 people how many books they had read in the past year. results indicated that x overb
kirill115 [55]
The confidence interval is

10.5\pm1.35 = (9.15, 11.85).  This means that we can be 99% confident that the mean number of books people read lies between 9.15 and 11.85.

To find the confidence interval, we first find the z-score associated with it:

Convert 99% to a decimal:  0.99
Subtract from 1:  1-0.99=0.01
Divide by 2:  0.01/2 = 0.005
Subtract from 1:  1-0.005 = 0.995

Using a z-table (http://www.z-table.com) we see that this is associated with a z-score between 2.57 and 2.58.  Since both are equally far from this value we will use 2.575.

We calculate the margin of error using

ME=z*\frac{s}{\sqrt{n}}
\\
\\=2.575*\frac{16.6}{\sqrt{1003}}=1.35

This means that the confidence interval is
10.5\pm1.35

The lower limit is given by 10.5-1.35 = 9.15.
The upper limit is given by 10.5+1.35 = 11.85
5 0
2 years ago
The travel time for a plane traveling at a rate of r kilometers per hour for 290 kilometers
Lapatulllka [165]
Time = distance / rate
time = 290 / rate

7 0
3 years ago
180 students in a tenth grade high school class take a survey about which video game consoles they own.
Fantom [35]

Answer:

P(A) = 44.44%

P(B) = 50%

P(B|A) = 37.5%

P(B|A) different from P(B).

A and B are independent.

Step-by-step explanation:

If we have a total of 180 students, and 80 of them have a Playstation, we have that P(A) = 80/180 = 0.4444 = 44.44%

If we have 90 students that have a Xbox, we have that P(B) = 90/180 = 0.5 = 50%

If we have 30 students that have both consoles, we have that P(A and B) = 30/180 = 0.1667 = 16.67%

To find P(B|A), we will find for a student that has an Xbox inside the group of students that has a Playstation, that is, we have 30 students in a total of 80 students, so P(B|A) = 30/80 = 0.375 = 37.5%

P(B|A) is different from P(B), the first is 37.5% and the second is 50%, so events A and B are independent events.

5 0
2 years ago
Due tonight<br>Please help!!!!!​
Harrizon [31]

angle BGC and angle BAD

7 0
3 years ago
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