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3 years ago

Find the slope of the line shown on the graph at right.

Mathematics

1 answer:

Bumek [7]3 years ago

7 0

to get the slope of a line, we only need two points, notice, the grid is using 2 numbers per line, so the point on the bottom-left is (-6,0) and the one on the upper-right is (6,4), so let's use those points.

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad
(\stackrel{x_2}{6}~,~\stackrel{y_2}{4})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-0}{6-(-6)}\implies \cfrac{4-0}{6+6}\implies \cfrac{4}{12}\implies \cfrac{1}{3}$

You might be interested in

Arrange these numbers from least to greatest:

Sindrei [870]

-3/7 is obviously the least because it is a negative number.Then 2/5 because if you think about it if 2/5 is 2 of 5 equal pieces. 2/3 is 2 of 3 pieces.So if you think about a pizza if you cut the pizza into 3 pieces and ate 2 imagine how much you would have left and then think about cutting the pizza into 5 pieces and only eating 2 . Think about that. So the answer in the end is -3/7,2/5, and then 2/3. Hope I helped!

8 0

3 years ago

Please answer quickly! Several questions from Algebra 2, on a unit about Sequences and Series, most of these have to do with Ari

AnnyKZ [126]

The sum of the geometric series is 2199; option E.

The 36th term of the arithmetic series is -60.5 option C
The sum of the arithmetic series is 2547; option E
The missing geometric sequence are; 1.614375, 3.30946875, 6.7844109375. option E

<h3>Arithmetic and Geometric series</h3>

a1 = 1458
r = 1/3
a6 = 6

S6 = a(rⁿ - 1) / r -1

= 1468(1/3^6 - 1) / (1/3 - 1)

= 1468(0.00137174211248 - 1) / -2/3

= 1468(-0.9986282578875) / -0.66666666666666

= -1,465.98628257885 / -0.66666666666666

= 2198.97942386829

Approximately,

S6 = 2199

Arithmetic series

a36
a1 = 27
d = -5/2

Sn = n/2{2a + (n -1)d}

= 36/2 {2×27 + (36-1)-5/2}

= 18{54 + (35)-5/2}

= 18(54 + 175/2)

= 18(54 + 87.5)

= 18(141.5)

s36 = 2547

a36 = a + (n - 1) d

= 27 + (36 - 1)-5/2

= 27 + (35)-5/2

=27 + -175/2

= 27 - 87.5

= -60.5

S20 = n/2{2a + (n -1)d}

= 20/2{2×27 + (20-1)-5}

= 10(54 + (19)-5)

= 10{54 + (-95)}

= 10(54-95)

= 10(-41)

s20 = -410

Missing terms of the geometric sequence:

nth term = ar^n-1

448/135 = 63/80×r^(6-1)

448/135 = 63/80×r^5

r^5 = 448/135 ÷ 63/80

= 448/135 × 80/63

= 35,840/8,505

r = 5√35,840/5√8505

= 946.57/461.11

r = 2.05

Second term = a×r

= 63/80×2.05

= 1.614375

Third term = ar²

= 63/80×2.05²

= 63/80×4.2025

= 3.30946875

Fourth term = 63/80 × 2.05³

= 63/80×8.615125

= 6.7844109375

Therefore, none of these are correct

Learn more about sum of geometric series:

brainly.com/question/24643676

#SPJ1

4 0

2 years ago

Pls help!! given: angles 1 and 2 are a linear pair prove that x=11

FinnZ [79.3K]

Step-by-step explanation:

2. Given: Angles 1 and 2 are a linear pair. Prove that x = 11 ma m = 11x-6 m2 = 4x+21 Statements Reasons 1) Angles 1 and 2 are a linear pair. 1) Given 2) Angles 1 and 2 are 2) Linear Pair Postulate supplementary 3) mZ1 + m2 = 180° 3) 4) 11x - 6 + 4x + 21 = 180 4) 5) 15x + 15 = 180 5) 6) 15x = 165 6) 7) x = 11 7)

I am not sure about my answer i dont want u to get wrong this is all i know i hope it was helpful

6 0

3 years ago

Consider the first five terms of the sequence 3, 15, 75, 375, 1875, … If the sequence defines a function, what is a reasonable d

matrenka [14]

Answer:

<h2>A reasonable domain is all natural numbers.</h2>

Step-by-step explanation:

Notice that the sequence begins with 3, and it's an infinite sequence, that's the meaning of the three points at the end.

So, a reasonable domain to this sequence, as function, it's all real numbers which follows the rule $f(x)=3(5)^{x-1}$ . In other words, the given sequence represents the range of the function, and the domain is defined by the number of terms, where the first term is 3, the second term is 15, and so on.

Therefore, a reasonable domain is all natural numbers.

8 0

3 years ago

Everyday, Dave eats either a sandwich or pizza for lunch. Over 42 days, Dave had pizza 3 times for every 4 times he had a sandwi

Elenna [48]

Remark

This problem drove 4 of us crazy until one of us made a break through.

Assumptions.

He must eat either 1 pizza a day or 1 sandwich a day. He can't eat 2 of anything during 1 day. So he can't eat 2 pizzas in a day or 2 sandwiches in a day.

Step One

Find the number of days in a cycle.

3 out of 4 days means out of 4 days he chooses Pizza

2 out of 3 days means out of 3 days he chooses a Sandwich.

That means that there are 4 + 3 days in total = 7 days in the cycle.

Step Two

Find the number of Pizzas and the number of Sandwiches he had during the 42 day period.

3/7 * 42 = Pizzas

3*6 = 18 pizzas in 42 days.

4/7* 42 = Sandwiches

4*6 = 24 sandwiches.

In 42 days he ate 24 + 18 = 42 lunches of either pizzas or sandwiches.

Step three This is the key step.

Find the ratio of sandwiches and pizzas for x days.

Every 5 days he either has 3 pizzas or 2 sandwiches. If the total number of days is x then

3/5 * x = Pizzas

2/5 * x = Sandwiches.

Step 4

Equate the results.

Pizzas = sandwiches.

18 + 3/5 x = 24 + 2/5 x Multiply by 5

18*5 + (3/5)*x * 5 = 24 * 5 + (2/5)*x*5

90 + 3x = 120 + 2x Subtract 2x from both sides

90 + 3x - 2x = 120

90 + x = 120 Subtract 90 from both sides.

x = 120 - 90

x = 30 days.

Conclusion

It takes 30 days to even up the number of pizzas with the number of sandwiches.

5 0

3 years ago