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Artist 52 [7]
3 years ago
8

In how many ways can I distribute $6$ identical cookies and $6$ identical candies to $4$ children, if each child must receive ex

actly $3$ items? (The requirement from part (a) is no longer in force -- that is, it's OK now to give a child $3$ items of one type and none of the other.)
Mathematics
1 answer:
Vinvika [58]3 years ago
7 0

Answer:

You can distribute the cookies and candies in four ways.

Step-by-step explanation:

Since cookies and candies are indistinguishable, we can use a combination. In this case represents the number of possible ways to distribute (without repetition) the cookies and candies (p) among a given number of children (n):

\begin{pmatrix}n\\ p\end{pmatrix}=\frac{n!}{p!(n-p)!}\\\begin{pmatrix}4\\ 3\end{pmatrix}=\frac{4!}{3!(4-3)!}=\frac{4!}{3!1!}=4

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A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.


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But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.

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3 years ago
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Step-by-step explanation:

To find how many games the team scored at least 70 points, we need to look at the 7 on the stem side. The 7 means 70, and we add the digits on the leaf side. For example, 7 | 2 is 72. The numbers on the leaf side are: 1, 1, 2, and 3.

There are no points for the 8 on the stem side, but on 90, there is one digit on the leaf side: 1. So, the points they scored over 70 are 71, 71, 72, 73, and 91, which equals to five games.

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Answer:

4% of all adults go to a health club at least twice a week

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Thus, the proportion of all adults go to a health club at least twice a week is

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3 years ago
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