As for this problem of true or false, the most probable answer the most likely one to be the correct answer would be A. True.
In Microsoft Word, or commonly referred to as MS Word, or simply Word itself as what is utilized in the problem, the program has the ability to recognize in spelling and grammar. When a red wavy underline is present, the word or words above it are usually wrong in spelling. Though this can be corrected by the user by adding the word in the dictionary so as not to be corrected in the future. The green one would be more about grammar. The blue wavy underline would indicate a word spelled correctly, but might be misused in the sentence it belongs. This usually happens to words that are almost identical in spelling like too and to.
Can prove they are not infringing on copyright
I believe its true because you can expand or collapse sections of it
The person watching Lances friend typing the ATM pin is an example of shoulder browsing. Lances friend should change the ATM pin.
<h3>What does ATM mean?</h3>
This is known as automated teller machine. It is said to be a kind of unique computer that makes it easy to manage a bank account holder's money.
Based on the above, The person watching Lances friend typing the ATM pin is an example of shoulder browsing. Lances friend should change the ATM pin so that his funds will not be stolen.
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Answer:
The correct answer to the following question is option "b".
Explanation:
The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).
- In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
- In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".
That's why the option "b" is correct.
