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3 years ago

How many deca meters are in 14 meters

Mathematics

2 answers:

makkiz [27]3 years ago

7 0

Answer:

1.4

Step-by-step explanation:

WITCHER [35]3 years ago

6 0

Answer:

1.4 decameters.

Step-by-step explanation:

Move the decimal point in 14. One to the right. This would equal to 1.4 . Hope this helps!

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2. Given the equation of a circle in standard form, identify the center, radius, and graph the circle.

Varvara68 [4.7K]

Answer:

Center: ( -1 , 2 )

Radius: 6

Step-by-step explanation:

The equation for a circle is given as follow:

$(x-h)^{2} +(y-k)^{2} =r^{2}$

Where,

the Center is: ( h , k ) (note that the signs of the number are different)

and the radius is: r

So if we compare the original circle equation to the equation in the question we can see that:

$(x+1)^{2} +(y-2)^{2} =36$

the Center is: (-1,2)

and the radius is: $\sqrt{36}$ = 6

2. To draw the graph find points that lay on the circle, it's better to take the values of x and y from the Center:

first sub y=2 in the equation to find the values for x:

$(x+1)^{2} +(y-2)^{2} =36$

$(x+1)^{2} +(2-2)^{2} =36$

$(x+1)^{2} +(0)^{2} =36$

$(x+1)^{2} =36$

$x+1 =±\sqrt{36}$

$x=6-1$ AND $x=-6-1$

$x=5$ AND $x=-7$

The points are A(5,2) and B(-7,2)

second sub x= -1 in the equation to find the values for y:

$(x+1)^{2} +(y-2)^{2} =36$

$(-1+1)^{2} +(y-2)^{2} =36$

$(0)^{2} +(y-2)^{2} =36$

$(y-2)^{2} =36$

$y-2=±\sqrt{36}$

$y=6+2$ AND $y=-6+2$

$y=8$ AND $y=-4$

The points are D(-1,8) and E(-1,-4)

After finding the points write them in the graph and match them together to get the like the circle in the picture below:

8 0

3 years ago

I need to do these math problems. Can some one help?

vlada-n [284]

Answer:

8 0

3 years ago

There are 20 students on the school's student council. A special homecoming dance committee is to be formed by randomly selectin

AysviL [449]

You can choose from 20 students for the first student, 19 for the second, 18 for the third, ..., 14 for the seventh student.

That gives you 20 * 19 * 18 * 17 * 16 * 15 * 14.

That number would allow you to write the students in different order. Since order here does not matter, any group with the same students in any order is the same group, you need to divide by the number of way you can order 7 items. Divide by 7 * 6 * 5 * 4 * 3 * 2 * 1

(20 * 19 * 18 * 17 * 16 * 15 * 14)/(7 * 6 * 5 * 4 * 3 * 2 * 1) = 77,520

Answer: 77,520

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME I GIVE BRAINLIEST

mariarad [96]

Decimal Form: 11.5

Fraction Form: 11 1/2

7 0

2 years ago

Read 2 more answers

Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e

saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in $R^{2}$ . To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

$\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle$

Now, let's calculate each vector length by calculating the norm.

$\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86$

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0

3 years ago