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Alecsey [184]
3 years ago
6

A duck swam 10.5 kilometers in 3 hours. how many kilometers per hour did the duck swim

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

3.5 km

Step-by-step explanation:

its 10.5 divided by 3 to get this answer

plz give me brainliest i need it plz

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The wholesale cost of a bicycle is $98.75.
mixer [17]

Answer:

$131.60

Step-by-step explanation:

For the promotion, markup is 33.3% of the selling price.

Now, Selling Price = Cost price + Cost price*Markup

Selling Price = $98.75 + $98.75*33.3%

Selling Price = $98.75 + $32.88375

Selling Price = $131.63375

Selling Price = $131.60

Thus, the selling price of the bicycle after calculating the markup is $131.60.

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B81%20%5Ctimes%208%7D%20" id="TexFormula1" title=" \sqrt{81 \times 8} " alt=" \sqr
laiz [17]

Answer:

Step-by-step explanation:

81 = 9 * 9 = 3 * 3 * 3 *3

8 = 2 * 2 * 2 *2

\sqrt{81 * 8 } = \sqrt{3*3*3*3*2*2*2}\\\\=3 * 3 * 2 \sqrt{2}\\\\= 18\sqrt{2}

6 0
2 years ago
What is the final cost of a $21,000 car with a sales tax of 7%?
fomenos
21,000 + 0.07(21,000) = 21,000 + 1,470 = 22,470
8 0
3 years ago
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Decompose 4/6 into three fractions with three different numerators
Anna007 [38]
2/3 6/9 9/12 are three fractions with different numerator
5 0
3 years ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
3 years ago
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