Answer:
The angle that the ramp forms with the ground is 27.5°
Step-by-step explanation:
Check the attachment for the figure.
Using the SOH CAH TOA trigonometry identity
For TOA
Tan(theta) = opposite/adjacent
Given opposite = 1.3m(side facing the angle of inclination
Adjacent = bottom of the ramp= 2.5m
Tan(theta) = 1.3/2.5
Tan(theta) = 0.52
theta = arctan0.52
theta = 27.5°
Answer:
see below
Step-by-step explanation:
f(x) = 4x^2 + 8x − 5
To find the x intercepts set y = 0
0 =4x^2 + 8x − 5
Factor
0=(2x-1)(2x+5)
Using the zero product property
2x-1 =0 2x+5 =0
2x=1 2x = -5
x = 1/2 x = -5/2
The x intercepts are ( 1/2 ,0) and ( -5/2,0)
Rewriting in vertex form by completing the square
4 ( x^2 + 2x) -5
4 ( x^2+2x +1) -4*1 -5
4 ( x+1) ^2 -9
Vertex form is
a( x-h) ^2 +k where ( h,k) is the vertex
The vertex is ( -1,-9)
We know it opens upwards since a > 0
Plot the vertex and the x intercepts
The graph is symmetric on based on the vertex
The probability is 0.246 or 24.6%.
We can use a binomial distribution for this:
Answer:
9
Step-by-step explanation:
9
Answer:
Yes it is a ploygon
convex
both
octagon
Step-by-step explanation: