Answer:
(a)
Distance from player should be 13.82 feet or 36.2 feet
(b)
The ball will go over the net
Step-by-step explanation:
we are given
The ball follows a path given by the equation
where
x and y are measured in feet and the origin is on the court directly below where the player hits the ball
(a)
net height is 8 ft
so, we can set y=8
and then we can solve for x
we can use quadratic formula
So, distance from player should be 13.82 feet or 36.2 feet
(b)
we can plug x=30 and check whether y=8 ft
we know that
height of net is 8 ft
so, the ball will go over the net
Answer:
The student is correct.
Step-by-step explanation:
Given that 5x² = 20:
It is true that the value of x = 2 because 2² = 4, and when you multiply 4 with 5, you'll get a product of 20:
5x² = 20
5(2)² = 20
5(4) = 20
20 = 20
Therefore, the student is correct that x = 2.
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
Answer:
The anwser is D 0.8
Step-by-step explanation:
Answer: The first answer choice
Step-by-step explanation:
