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leva [86]
4 years ago
12

What is the GCF of 120, 36

Mathematics
2 answers:
Novosadov [1.4K]4 years ago
6 0
The GCF of 120 and 36 is 12
andrezito [222]4 years ago
4 0

12 is the great common factor in this problem.

Find the prime factorization of 120

120 = 2 × 2 × 2 × 3 × 5

Find the prime factorization of 36

36 = 2 × 2 × 3 × 3

To find the gcf, multiply all the prime factors common to both numbers:


Therefore, GCF = 2 × 2 × 3

GCF = 12

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Answer:

The answer is 0.157

Step-by-step explanation:

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Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of z=0-2i. First, convert from Cartesian to polar form:

r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2

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Next, use the formula \displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr] where \displaystyle k=0,1,2,...\:,n-1 to find the square roots:

<u>When k=1</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]

\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)

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<u>When k=0</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)

\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i

Thus, the square roots of -2i are 1-i and -1+i

4 0
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Lesechka [4]

Answer:

C.

Step-by-step explanation:

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