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Sati [7]
2 years ago
12

Each of the 14 students in the art club needs 4 1/4 ounces of paint for a project. The art store sells paint only in 8 ounce bot

tles. How many bottles of paint does the art club president need to buy for the project?
A - 3
B - 4
C - 7
D - 8
Mathematics
2 answers:
Blababa [14]2 years ago
7 0

Answer:

C-7

Step-by-step explanation:

Answer:  The art club president need to buy 14 bottles of paint for the project.

Step-by-step explanation:  Given that each of the 14 students in the art club needs 4 ounces of paint for a project. The art store sells paint only in 8-ounce bottles.

We are to find the number of bottles of paint that the art club president need to buy for the project.

We will be using the unitary method to solve the given problem.

Number of bottles filled by 8 ounces of paint = 1.

So, the number of bottles filled by 1 ounce of paint is

So, the number of bottles filled by 4 ounces of paint will be

Now, number of bottles of paint needed by 1 student  

Therefore, the number of bottles of paint needed by 14 students will be

Thus, the art club president need to buy 14 bottles of paint for the project.

notka56 [123]2 years ago
7 0
The answer is C-7!!!
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Step-by-step explanation:

Count all the add numbers in 1-10 then add the 4 and you get

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3 years ago
What are the relative frequencies, to the nearest hundredth, of the rows of the two way table?
Nookie1986 [14]

Answer:            A         B

Group A        0.25      0.75

Group B        0.45      0.55

Step-by-step explanation:

Since we have given that

Number of people of A in Group A = 15

Number of people of B in Group A = 45

Number of people of A in Group B = 20

Number of people of B in Group B = 25

Total number of people in Group A = 15+45 = 60

Total number of people in Group B = 20+25 = 45

So, Relative frequencies will be given  below:

Relative frequency of A in Group A is given by

\frac{15}{60}=0.25

Relative frequency of B in Group A is given by

\frac{45}{60}=0.75

Relative frequency of A in Group B is given by

\frac{20}{45}=0.45

Relative frequency of B in Group B is given by

\frac{25}{45}=0.55

Hence,             A         B

Group A        0.25      0.75

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Will mark brainliest! Questions are in the picture!
alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the <u>perimeter </u>to the nearest tenth.

As we know that the area of triangle is ,

\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)

Substituting the respective values,

\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0

On using the <u>Quadratic</u><u> formula</u> , we have;

\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}

On simplifying above , we will get ,

\rm\longrightarrow x = 6.802,-9.802

Since sides can't be negative, therefore,

\rm\longrightarrow\underline{\underline{ x =6.802}}

Therefore ,

  • \rm\longrightarrow Base = 3x =3(6.802)in = 20.406\ in\\
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Next let's find out the <u>hypotenuse </u>using Pythagoras theorem, as ;

\rm\longrightarrow h=\sqrt{ b^2+p^2}\\

\rm\longrightarrow h =\sqrt{ (20.406)^2+(9.802)^2}\\

\rm\longrightarrow h =\sqrt{416.40+96.07}\\

\rm\longrightarrow h = 22.63\ in

Now we may find perimeter as ,

\rm\longrightarrow P = p + b + h \\

\rm\longrightarrow P = (22.63 + 9.802 + 20.406)in.

\\\rm\longrightarrow P = 52.89 \ in.\\

\rm\longrightarrow \underline{\underline{ Perimeter = 52.9\ in .}}

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