Answer:The agency problem is a conflict of interest inherent in any relationship where one party is expected to act in another's best interests. In corporate finance, the agency problem usually refers to a conflict of interest between a company's management and the company's stockholders.
Explanation: Brainlist please
Answer:
He could have shut off the power first and de-energize the circuits in order to prevent being electrocuted.
Explanation:
Electrical Safety is very important, <em>especially for those working in such hazardous situations. </em>Almost all our things in the society are electrically-operated, thus it even becomes relevant to have an idea on how we can prevent from obtaining an electrical shock or burns due to faulty electrical tools.
In the worker's scenario above, it is clear that he did not shut off the power at the circuit breaker panel. This is the most important thing that one must include in his plan when attempting to correct an electrical problem. You must find where the electrical switch, fuses and circuit breakers are at first. Once you find their location, you have to turn them off (even if the circuits are of low-voltage).<u> In order to make sure that they are really turned off, test the circuits first. This will help you ensure that they are, indeed, de-energized.</u>
X^2-8x+41=0
x-8x+41=0
-7x+41=0
-7x=-41
x=41/7
Hope that helped :D
A) The x-component of the shot's acceleration while in flight is; aₓ = 0 m/s²
B) The y-component of the shot's acceleration while in flight is;
a_y = -9.8 m/s²
C) The x-component of the shot's velocity while in flight is; vₓ = 7.55 m/s
D) The y-component of the shot's velocity while in flight is;
a_y = 9.32 m/s
<h3>Projectile motion</h3>
A) The x-component of the shot's acceleration while in flight?
aₓ = 0 m/s²
B) Since the object is thrown vertically, it means that it is against gravity and as such acceleration due to gravity will be negative,
Thus, the y-component of the shot's acceleration while in flight is;
a_y = -9.8 m/s²
C) The x-component of the shot's velocity at the beginning of its trajectory is; v_x = v cos θ
v_x = 12 cos 51
v_x = 7.55 m/s
D) The y-component of the shot's velocity at the beginning of its trajectory is; v_y = v sin θ
v_y = 12 sin 51
v_y = 9.32 m/s
Read more about Projectile Motion at; brainly.com/question/11049671
