Una fuerza F de 200 lb actúa a lo largo de AB, sobre la rampa mostrada. fuerza de F respecto del eje OC. Calcule el momento de f
uerza de F respecto del eje OC
1 answer:
Answer:
Moc = -613.25 [lb*in]
Explanation:
Este problema se puede resolver mediante la mecánica vectorial, es decir se realizara un analisis de vectores.
Primero se calculara el momento de la fuerza F_AB con respecto al punto O, debemos recordar que el momento con respecto a un punto se define como el producto cruz de la distancia por la fuerza.
(producto cruz)
Necesitamos identificar los puntos:
O (0,0,0) [in]
A (12,0,0) [in]
B (0, 24,8) [in]
C (12,24,0) [in]
El ultimo vector calculado corresponde al vector unitario (magnitud = 1) de AB. El vector fuerza corresponderá al producto del vector unitario por la magnitud de la fuerza = 200 [lb].
De esta manera realizando el producto cruz tenemos
Para calcular el momento con respecto a la diagonal OC, necesitamos el vector unitario de esta diagonal.
El vector con respecto al eje OC, es igual al producto punto del momento en el punto O por el vector unitario LOC
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where:
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c)
The electric potential created by S1 at the level or S2 is 360V
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d) The force exerted by S2 on S1 will be the same in magnitude as the force exerted by S1 on S2 but oposite in direction. This is because the force will depend on the two charges, and the distance between them, so:
The electric force exerted by S1 on S2 is 21.58μN.
The magnitude of the force is determined by using the following formula:
So the force will be equal to:
which is the same as:
e) The electric field generated by S1 in the middle of S1 and S2 is
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f) The electric field in the middle of S1 and S2 is
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where:
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h)
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