A student is investigating magnetic fields. The student places four different objects near identical magnets and observes what h
appens. The student records her observations in the table below. Using data from the table, which argument can the student make about magnetic fields?
a. The effect that a magnetic field has on an object depends on the mass of the object.
b. The effect that a magnetic field has on an object depends on the material of the object.
c. The effect that a magnetic field has on an object depends on the type of magnet used.
d. The effect that a magnetic field has on an object depends on the distance to the object.
a. The effect that a magnetic field has on an object depends on the mass of the object.
b. The effect that a magnetic field has on an object depends on the material of the object.
c. The effect that a magnetic field has on an object depends on the type of magnet used.
d. The effect that a magnetic field has on an object depends on the distance to the object.
2 answers:
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Answer:
The ball will drop 0.881 m by the time it reaches the catcher.
Explanation:
The position of the ball at time "t" is described by the position vector "r":
r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)
Where:
x0 = initial horizontal position.
v0x = initial horizontal velocity.
t = time.
y0 = initial vertical position.
v0y = initial vertical velocity.
g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).
When the ball reaches the catcher, the position vector will be "r final" (see attached figure).
The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.
Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):
x = x0 + v0x · t
17.0 m = 0 m + 40.1 m/s · t
t = 17.0 m/ 40. 1 m/s = 0.424 s
With this time, we can calculate the y-component of the vector "r final", the drop of the ball:
y = y0 + v0y · t + 1/2 · g · t²
Initially, there is no vertical velocity, then, v0y = 0.
y = 1/2 · g · t²
y = -1/2 · 9.8 m/s² · (0.424 s)²
y = -0.881 m
The ball will drop 0.881 m by the time it reaches the catcher.
