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4 years ago

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Mathematics

2 answers:

alexira [117]4 years ago

8 0

Answer:

Step-by-step explanation:

Alex73 [517]4 years ago

7 0

Answer:

$2 {x}^{3} + 1.5 {x}^{2} - 5x$

Step-by-step explanation:

Multply f(x)*g(x)

((x/2)/2)*(2x^2+x-3)

First get (f+g)

f+g=(x/2)-2)+(2x^2+x-3)

multply all eqn by 2

2(f+g)= x -4+4x^2+2x-6

2(f+g)= 4x^2+3x-10

devide by 2

(f+g) = 2x^2 + 1.5x -5

(f+g)(x) =

$2 {x}^{3} + 1.5 {x}^{2} - 5x$

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Step-by-step explanation:

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Solving the equation

liubo4ka [24]

Answer:

y = 5

Step-by-step explanation:

Step 1: Write equation

-(4y + 2) - (-3y - 6) = -1

Step 2: Solve for <em>y</em>

Distribute: -4y - 2 + 3y + 6 = -1
Combine like terms: -y + 4 = -1
Subtract 4 on both sides: -y = -5
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Step 3: Check

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3 years ago

Will give brainiest In △ABC, angle bisectors

EleoNora [17]

Answer:

$m\angle CAB=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=25\dfrac{5}{7}^{\circ}$

Step-by-step explanation:

AK is angle A bisector, then

$m\angle BAK=m\angle KAC=x^{\circ}$

BL is angle B bisector, then

$m\angle ABL=m\angle CBL=y^{\circ}$

Consider triangle ABL. The sum of the measures of all interior angles in this triangle is $180^{\circ},$ then

$m\angle BAL+m\angle ALB+m\angle LBA=180^{\circ}\\ \\2x+2y+y=180\\ \\2x+3y=180$

Consider triangle ABK. In this triangle,

$m\angle AKB=180^{\circ}-2x^{\circ} \ [\text{Supplementary angles}]$

The sum of the measures of all interior angles in this triangle is $180^{\circ},$ then

$m\angle BAK+m\angle AKB+m\angle KBA=180^{\circ}\\ \\x+(180-2x)+2y=180\\ \\2y-x=0$

Hence,

$x=2y\\ \\2(2y)+3y=180\\ \\4y+3y=180\\ \\7y=180\\ \\y=\dfrac{180}{7}=25\dfrac{5}{7}\\ \\x=\dfrac{360}{7}=51\dfrac{3}{7}$

Find the measures of the triangle ABC:

$m\angle CAB=2x^{\circ}=102\dfrac{6}{7}^{\circ}\\ \\m\angle ABC=2y^{\circ}=51\dfrac{3}{7}^{\circ}\\ \\m\angle ACB=180^{\circ}-102\dfrac{6}{7}^{\circ}-51\dfrac{3}{7}^{\circ}=25\dfrac{5}{7}^{\circ}$

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4 years ago