Answer:


n = 50
A) show the sampling distribution of x, the sample mean average for a sample of 50 unemployment individuals.
We will use central limit theorem
So, mean of sampling distribution = 
Standard deviation of sampling distribution = 
B) What is the probability that a simple random sample of 50 unemployment individuals will provide a sample mean within one week of the population mean?
A sample mean within one week of the population mean means 
So, 
=
=
=
=0.9616-0.0384
=0.9232
The probability that a simple random sample of 50 unemployment individuals will provide a sample mean within one week of the population mean is 0.9232.
C) What is the probability that a simple random sample of 50 unemployed individuals will provide a sample mean within a half week of the population mean?
A sample mean within one week of the population mean means 
So, 
=
=
=
=0.8106-0.1894
=0.6212
The probability that a simple random sample of 50 unemployed individuals will provide a sample mean within a half week of the population mean is 0.6212
Answer:

Step-by-step explanation:

Answer:
D
Step-by-step explanation:
<em>Midpoint Formula:</em>

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Answer:
The answer is 50%.
Step-by-step explanation:
I did the question on IXL, and got it right.
Answer:
27 cm
Step-by-step explanation:
So the ratio you have is
width(x) : length (36)= 3:4
Divide 36 (length) by the ratio length. 36÷4=9
They are multiples of nine, so multiply the width by 9 to get the 3.
3×9=27
You have 27:36
If you want to check it, divide both by 9 and you get 3:4