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Bas_tet [7]
3 years ago
5

Enter the value of n so the expression (-y+ 5.3) + (7.2y-9) is equivalent to 6.2y+n.

Mathematics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

\boxed{\bold{Decimal: \ n \ = \ -3.7}}

\boxed{\bold{Fraction: \ n=-\frac{37}{10}}}

Step By Step Explanation:

Rewrite Equation:

\bold{\left(-y+5.3\right)+\left(7.2y-9\right)=6.2y+n}

Switch Sides:

\bold{6.2y+n=\left(-y+5.3\right)+7.2y-9}

Remove Parenthesis: (a) = a

\bold{6.2y+n=-y+5.3+7.2y-9}

Group Like Terms:

\bold{6.2y+n=-y+7.2y+5.3-9}

Combine Similar Elements: \bold{-y+7.2y=6.2y}

\bold{6.2y+n=6.2y+5.3-9}

Subtract: \bold{5.3-9=-3.7}

\bold{6.2y+n=6.2y-3.7}

Multiply Both Sides By 10:

\bold{6.2y\cdot \:10+n\cdot \:10=6.2y\cdot \:10-3.7\cdot \:10}

Refine:

\bold{62y+10n=62y-37}

Subtract 62y From Both Sides:

\bold{62y+10n-62y=62y-37-62y}

Refine:

\bold{10n=-37}

Divide Both Sides By 10:

\bold{\frac{10n}{10}=\frac{-37}{10}}

Simplify:

\bold{n=-\frac{37}{10}}

Turn Fraction Into Decimal:

\bold{-37 \ \div \ 10}

Refine:

\bold{-3.7}

- Mordancy

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Ostrovityanka [42]
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-6x=36 /(-6)
x=-6
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4 years ago
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solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

3 0
3 years ago
Solve for the variable in the following equation: 1 / 6c + 1 / 3 = - 2
tankabanditka [31]

Answer: C. C=-14

Step-by-step explanation:

Given

(1/6)c+1/3=-2

Multiply both sides by the LCM of 1/6 and 1/3(Least Common Multiple)

6[(1/6)c+1/3]=(-2)(6)

c+2=-12

Subtract 2 on both sides

c+2-2=-12-2

c=-14

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
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Answer this as quick as possible please! (NO EXPLANATION REQUIRED!) &lt;3
shtirl [24]

Answer: 9 Apples

Step-by-step explanation:

Given the following :

Total number of bags = 12

Mean of the distribution(m) = 8

Number of apples (x):

6 - - - - 7 - - - - 8 - - - - 9 - - - - 10

Frequency (f) :

1 - - - - 4 - - - - 2 - - - - 3 - - - - 1

Therefore :

Let number of apples in the 12th bag = y

Frequency of 12th bag : (12 - 11) = 1

Mean of distribution(m) :

Sum of ( f * x) / sum of f

Sum of (f * x) = (6*1)+(7*4)+(8*2)+(9*3)+(10*1)+(y*1)

Sum of (f * x) = (6+28+16+27+10+y) = 87 + y

Sum of f = 12

From :

m = Sum of ( f * x) / sum of f

8 = (87 + y) / 12

87 + y = 12 * 8

87 + y = 96

y = 96 - 87

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ratelena [41]

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