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Andrej [43]
3 years ago
15

Please help me. URGENTTTTR thanks :)

Mathematics
1 answer:
Andru [333]3 years ago
6 0
Help you with what?
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What is the value of 3 + x when x = 19?
zavuch27 [327]

Answer:

Its 22

Step-by-step explanation:

x is 19

so 3+19 is 22

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3 years ago
Solve for y. 12x +2y = 26x -70 a) y= 7x - 35 b) y= 20x -35 c) y= 2x + 72 d) x= 2y +36x -70 I CAN'T TELL IF IM DUMB OR NOT
Zepler [3.9K]

Answer:

Step-by-step explanation:

12x + 2y = 26x - 70

2y = 14x - 70

y = 7x - 35

the answer is A

6 0
3 years ago
Read 2 more answers
Your friend is trying to calculate the height of a nearby oak tree. You tell him that you learned how to use similar triangles i
elena-s [515]

Answer:

59.38 ft

Step-by-step explanation:

The person and his shadow form a triangle. The tree and its shadow also form a triangle. The triangles are similar triangles, so the lengths of corresponding sides are proportional.

Let the unknown tree height be h.

(person's height)/(person's shadow) = (tree height)/(tree's shadow)

(75 in.)/(48 in.) = h/(38 ft)

(25)/(16) = h/(38 ft)

16h = 25 * 38 ft

16h = 950 ft

h = 59.375 ft

h = 59.38 ft

6 0
3 years ago
Multiply. Write your answer in simplest form 1\9 X3/10<br>help fast i will give 5 stars
photoshop1234 [79]

Answer:

1/30

Step-by-step explanation:

1/9 x 3/10 = 3/90 = 1/30

7 0
4 years ago
what key feature(s) can be easily identified from factored form? explain how each key feature is related to the roller coaster.
Ulleksa [173]

Answer:

Step-by-step explanation:

With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0

As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.

At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)

we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.

we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔  m.

It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m

6 0
3 years ago
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