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2 years ago

Estimate how many hours it take a shark to swim 200 miles if he swims 33 mph

Mathematics

2 answers:

babymother [125]2 years ago

8 0

Approximately 6 hours

TiliK225 [7]2 years ago

6 0

It would take approximately 6.06 hours because you have to divide 33 by 200.

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Part C

mel-nik [20]

Answer:

Tamara needs to cover a total of 476 square feet.
Tamara will have enough material to cover all four walls.

Step-by-step explanation:

If the room dimensions are 8 1/3 feet by 11 1/2 feet, the perimeter length is ...

P = 2(L+W) = 2(8 1/3 +11 1/2) = 2(19 5/6) = 39 2/3 feet

The area of the walls is the product of this perimeter length and the height of the wall. If that height is 12 feet, then the wall area is ...

A = PH = (39 2/3 ft)(12 ft) = 476 ft²

Tamara needs to cover a total of 476 square feet.

If Tamara orders 480 square feet of material, ...

Tamara will have enough to cover all four walls.

6 0

2 years ago

the hardwere store sold 7,389 boxes of nails last year. they aold 9,125 boxes of screws. how many more boxes of screws did they

Naily [24]

1,784 because 9,125 - 7,389 = 1,784

7 0

2 years ago

Read 2 more answers

Solve 6x+89(9)^2 3(2x+2403) 3(2x+234) 6x+7209 which one would it be

iogann1982 [59]

Answer:

It would be the last one 6x+7209

Step-by-step explanation:

because it will be simplify not factor by

6 0

2 years ago

Read 2 more answers

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

3 years ago

Please help me I don’t know what to do

Lisa [10]

Answer:

(x-3,y-4) = correct

Step-by-step explanation:

5 0

1 year ago