(0,-3)
Was the two supposed to be on the top
When a function is shifted to the right by 1 unit it is moved towards the negative side so we would be adding -1 to the value of x. The function f(x) would be f(x-1). To determine the resulting function, we substitute to the parent function (x-1) to x. We do as follows:
<span>f (x) = x^3 + 2x^2 − 3x − 5
</span>f (x-1) = (x-1)^3 + 2(x-1)^2 − 3(x-1) − 5
f (x-1) = x^3 - 3x^2 + 3x - 1 + 2(x^2 - 2x + 1) - 3x + 3 - 5
f (x-1) = x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5
f (x-1) = <span>x^3 - x^2 - 4x - 1
Therefore, the correct answer is the last option.</span>
Answer:
IF IT IS THE AREA THEN YOU SHOULD TIMES THEM AS IN THE 1ST SHAPE 3 X 7 X 6 THEN DIVIDE 2 SECOND 7 X 3 X 3 X 6 DIVIDE INTO 2 AND AGAIN 2
Step-by-step explanation:
IT WILL BE EASY FOR YOUR EXAM
Answer:
8064
Step-by-step explanation:
14 x 12= 168
168 x 48= 8064
Step-by-step explanation:
F(x) = ∫ₐˣ t⁷ dt
F(x) is the area under f(t) between t=a and t=x. When x=a, the width of the interval is 0, so the area is zero.
F(6) = 0, so a = 6.
F(x) = ∫₆ˣ t⁷ dt
F(6) = ∫₆⁶ t⁷ dt
F(6) = 0
