Answer:
2
Step-by-step explanation:
It sounds like we are pretending A is the universe. The only numbers in our world are 1,2,3,4, and 5.
You are given B is all numbers greater than 2.
The complement of B would all the elements not listed in B.
The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.
The elements not in B are 1 and 2.
So B complement is {1,2}.
There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.
Answer:
Yes
Step-by-step explanation:
ΔMNL ≅ ΔQNL by ASA or AAS
by ASA
Proof:
∠ LNM = ∠LNQ =90
LN = LN {Common}
∠MLN = ∠QLN {LN bisects ∠ L}
By AAS
∠Q + ∠QLN + ∠LNQ = 180 {Angle sum property of triangle}
∠Q + 32 + 90 = 180
∠Q + 122 = 180
∠Q = 180 -122 =
∠Q = 58
∠Q = ∠M
∠MNL =∠QNL = 90
LN = LN {common side}
Answer:
It is the 2nd answer choice 4 check 5
Step-by-step explanation:
576^2 = 24 ÷ 3 = 8 × 2r = 8 × 6 = 48
Answer: 900
Step-by-step explanation:
