The area would be 63.The steps to how I got that anwser:
1.] Write your formula
A=bh
----
2
2.]Begin by plugging in your measurements
A=7.5 times 16.8
-------------------
2
3.]Multiply the top two numbers together
A=126
-----
2
4.]Divide to get your final anwser
A=63
Answer:
1/15
Step-by-step explanation:
Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.
For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.
2/6 x 1/5 = 1/15
Answer:

Step-by-step explanation:
Please refer to the attachment.
By AA Similarity, the two triangles are similar.
Therefore, corresponding parts of them are proportional.
Therefore, we can write the following proportion:

We will solve for x. Cross-multiply:

Distribute:

Subtract 21 from both sides:

Divide both sides by 7. So, the value of x is:

However, that is only the value of x.
The shadow of the tree is (x+3).
Hence, we will need tot add 3 to our value. Therefore, the actual length of the shadow of the tree is approximately:

√x² - 4 + x²/x² + 1
x - 2 + x²/x² + 1
<u>x - 2</u> + <u> x² </u>
1 x² + 1
<u>(x - 2)(x² + 1)</u> +<u> x² </u>
(1)(x² + 1) x² + 1
<u>x³ + x - 2x² - 2</u> + <u> x² </u>
x² + 1 x² + 1
<u>x³ - 2x² + x² + x - 2</u>
x² + 1
<u>x³ - x² + x - 2</u>
x² + 1
x³ + x - 2
Part A)<span>In a 45-45-90 triangle, what is the length of the hypotenuse when the length of one of the legs is 11 in.?
we know that
</span>cos 45°=√2/2
[he length of the hypotenuse]=11/cos 45-----------> 11/(√2/2)----> (11*2)/√2
=22/√2-------> 11√2 in
the answer Part A) is 11√2 in
Part B) <span>What is the exact value of sin 45° ?
</span>
we know that
sin 45°=11/(11√2)-------> 1/√2---------> (1/√2)*(√2/√2)-----> √2/2
the answer part b) is √2/2
Part C)
<span>What is the area of a regular hexagon with a side length of 4 m?
we know that
</span>In case of a regular hexagon <span> each of the six triangles that are formed by connecting its center with all six vertices is an equilateral triangle with a side equaled to 4 m.
The area of this hexagon is six times greater than the area of such a triangle
</span>
In an equilateral triangle with a side d<span>
the altitude </span>h can be calculate from the Pythagorean Theorem as
h²=d²−(d/2)²=(3/4)d²
<span>Therefore,
</span><span>h=d<span>√3/2
</span></span><span>Area of such a triangle is
</span>A=d*h/2------------> d²*√3/4
From this the area of the regular hexagon with a side d<span> is
</span>S=6*A----------> d²3√3/2
for d=4 m
S=4²3√3/2------> 24√3 m²------------> 41.57 m²
the answer Part C) is 41.57 m²
Part D) <span>In a 30-60-90 triangle, what is the length of the hypotenuse when the shorter leg is 5 cm?
</span>[he length of the hypotenuse]=5/sin 30--------> 5/(1/2)---------> 10 cm
the answer part D) is 10 cm