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Ratling [72]
3 years ago
10

Find the product of 5/6( 1/2) * O 6/8 O 5/12 O 5/6

Mathematics
2 answers:
inysia [295]3 years ago
6 0
The anser is 6/8 that what i think
maksim [4K]3 years ago
5 0

Answer:

6/8

Step-by-step explanation:

yep 6/8

aaaaaaaaaaaaaaaaaaa

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What is 1/5 of 11????????????
Helga [31]
Multiply 1/5 by 11 to get 2.2, to check, multiply 2.2 by 5. The answer though, is 2.2.
7 0
3 years ago
Help meeeeeee bruhfffff
Serjik [45]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>y = 15, -15</em>

▹ Step-by-Step Explanation

This is considered a 'square root' since we have to find y^2.

15 * 15 = 225

-15 * -15 = 225

Both of these values work for y, so the answer is 15, -15.

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

4 0
3 years ago
Read 2 more answers
Can somebody help me with this question
ArbitrLikvidat [17]
What you need to do is find the greatest amount (1) and the lowest amount (1/4) of sap collected and the find how many times the lowest can go into the greatest. (So how many times can 1/4 go into 1). I believe that this is how you would do that.
8 0
3 years ago
D) Use your knowledge of scale drawings and image sizes to fill in the missing
astraxan [27]

Answer:

  Your table is filled in below.

Step-by-step explanation:

The scale factor is the ratio of image size to original size. In part (d), the image height is "blocks" while the original height is "feet". So, the units of the scale factor are "blocks/ft".

Sometimes a scale factor has units, like this, and sometimes it is expressed as a pure number. A map scale factor might be the pure number ratio 1 : 62500, or it could also be expressed with units as 1 in : 1 mile.*

__

* actually, these are slightly different scales. 1:62500 is about 0.98643 inches per mile.

7 0
3 years ago
Read 2 more answers
In the triangle shown we can find the angle θ as follows calculator
Xelga [282]
Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.

\sin\theta= \frac{opposite}{hypothenuse} = \frac{30}{34} = \frac{15}{17}  \\  \\ \Rightarrow \theta=\sin^{-1}\left( \frac{15}{17} \right) \\  \\  \\ \cos\theta= \frac{adjacent}{hypothenuse} = \frac{16}{34} = \frac{8}{17}  \\  \\ \Rightarrow \theta=\cos^{-1}\left( \frac{8}{17} \right) \\  \\  \\ \tan\theta= \frac{opposite}{adjacent} = \frac{30}{16} = \frac{15}{8}  \\  \\ \Rightarrow \theta=\cos^{-1}\left( \frac{15}{8} \right)
3 0
3 years ago
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