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kondaur [170]
3 years ago
7

Suppose a plant grow one inch every year if X is how old the plant is (years) and f(x) is how tall the plant is (in inches) what

type of function is f(x)?
A. constant function
B. identity function
C. absolute value function
D. step function
Mathematics
1 answer:
miskamm [114]3 years ago
5 0
It’s C. absolute value function
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Order the following from greatest to least 1/4, 0.33, 1/8, 0
schepotkina [342]

Answer: 0.33 , 1/4 , 1/8 , 0

Step-by-step explanation:

1/4 is 0.25

1/8 is 0.125

After converting to decimal it’s all easy

4 0
3 years ago
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Find the HCF of 27, 63, 54 using prime factorization method.
Step2247 [10]

Answer:

27 = 3 , 3, 3

63= 3 , 3, 7

54= 3 , 3, 3, 2

HCF OF 27, 63 AND 54 = 3 X 3 = 9

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7 0
2 years ago
1. A plane is flying at an altitude of 13000 feet. The angle of depression from the plane to a control tower is 20 degrees. The
Mariulka [41]

Answer:

see explanation

Step-by-step explanation:

There is a right triangle formed between the height above the tower to the plane, the horizontal and the line from the tower to the plane.

The height above the tower to the plane = 13000 - 150 = 12850 ft

The angle between the plane and the tower is 20° , angle of depression.

Using the tangent ratio in the right triangle formed, with the adjacent side being the horizontal ( hor ) distance, then

tan20° = \frac{opposite}{adjacent} = \frac{12850}{hor} ( multiply both sides by hor)

hor × tan20° = 12850 ( divide both sides by tan20° )

hor = \frac{12850}{tan20} ≈ 35305 ft ( to the nearest foot )

(2)

Arianna is 60 + 5 = 65 ft above the ground ( to her eye level )

Using the right triangle formed with legs 65 and 37  and angle of depression x, then

tanx° = \frac{opposite}{adjacent} = \frac{37}{65} , thus

x = tan^{-1} (\frac{37}{65} ) ≈ 30° ( to the nearest degree )

4 0
3 years ago
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What are the solutions of x² + 6x - 6 = 10?
Likurg_2 [28]

Answer: x=- 8 or x=2


Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. The quadratic  equation is:

x^{2}+6x-6-10=0\\x^{2}+6x-16=0

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}

x_1=-8\\x_2=2


4 0
3 years ago
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Which is a correct two column proof. Given &lt;4 and
vladimir1956 [14]

The initial statement is:    QS = SU   (1)

                                    QR = TU    (2)

 

We have to probe that:  RS = ST

 

 

Take the expression (1):                     QS       =   SU

We multiply both sides by R                (QS)R   =   (SU)R

 

 

But    (QS)R = S(QR)     Then:            S(QR)   =   (SU)R     (3)

 

From the expression (2):  QR = TU. Then, substituting it in to expression (3):

 

                                                       S(TU)   =   (SU)R     (4)

 

But  S(TU) = (ST)U  and (SU)R = (RS)U

 

Then, the expression (4) can be re-written as:

 

                                                      (ST)U    =    (RS)U

 

Eliminating U from both sides you have:     (ST) = (RS)    The proof is done.

4 0
3 years ago
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