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ehidna [41]
3 years ago
12

Need help with 1, 2, 3 , 4 & 5

Mathematics
1 answer:
const2013 [10]3 years ago
4 0

Answer:

you add the titkgik4ifitit

you add

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Which of the following are solutions to the quadratic equation? Check all that apply x^2 + 12x + 36 = 7
garik1379 [7]

Answer:

x = -6 + \sqrt{7}, x = -6 - \sqrt{7}

Step-by-step explanation:

(x + 6)² = 7

x + 6 = + or - \sqrt{7}

x = -6 + \sqrt{7}, x = -6 - \sqrt{7}

5 0
3 years ago
Write an equation in slope-intercept form of the line that passes through the point (-2,1) and is perpendicular to the equation
blondinia [14]
Let's convert the equation into slope-intercept form.

3x + 18y = 4
Subtract 3x from both sides.
18y= -3x + 4
Divide both sides by 18.
y = -3/18x + 4/18
Simplify.
y = -1/6x + 2/9

To make a line perpendicular, we need the slope to be the reciprocal of the other. Flip the denominator and numerator, and change the sign. We also have to change the b to make the line go through (-2, 1)

-1/6 to +6/1, or 6.

y = 6x + b

Input the x and y values and solve for b.

1 = 6(-2) + b
1 = -12 + b
Add 12 to both sides.
13 = b

y = 6x + 13
5 0
3 years ago
The product of which expression contains four decimal places?​
dalvyx [7]

Answer: we need to see the problem

Step-by-step explanation:

3 0
4 years ago
The sequence 2, 3, 5, 6, 7, 10, 11, $\ldots$ contains all the positive integers from least to greatest that are neither squares
sergeinik [125]
The 400th term is 425.

There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are \lfloor\sqrt[6]{427}\rfloor=2 numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 = 425.
7 0
3 years ago
Which system of equations has no solutions? 9 NW AUOVO 5 -NW A o Voor 1 o 1 2 3 4 5 6 7 8 9 O 1 2 3 4 5 6 7 8 9 X O O O O MN 7.
dusya [7]

Answer:

the one with one line and the one that is parallel, Basically the two on top^_^

3 0
3 years ago
Read 2 more answers
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