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monitta
3 years ago
12

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 55°, a = 12, b = 14

Mathematics
2 answers:
Mkey [24]3 years ago
6 0
The way you'd set it up would be sin55º/12=sinB/14 (you could also flip the equation so that 12/sin55º=14/sinB, you'll get the same answer either way). Multiply out so that its 14•sin55º=12•sinB, or 11.47=12•sinB. Divide both sides by 12 so that it looks like .96=sinB, then take arcsine of both sides (arcsin= x=sin^-1 theta+360n or x=180- (sin^-1 theta)+360n), which should give you about 72.88º and 107.12º.
poizon [28]3 years ago
4 0

Answer:

B = 72.9°, C = 52.1°, c = 11.6; B = 107.1°, C = 17.9°, c = 4.5

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Write the equation of the line that passes through the point (7,-1) that has a slope of 0.
lora16 [44]

Answer:

y=0x-1

Step-by-step explanation:

y=0(x)+c

-1=0(7)+c

-1=0+c

C=-1

8 0
3 years ago
48+2x a la 2 -x a la 4
galben [10]

Answer: −a5lx+2a3lx+48 (assuming that the a and the la are variables)

Step-by-step explanation:

48+2xala2−xala4

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3 0
3 years ago
The red dot is about half way between 12 and 13
stepladder [879]

Answer:

It is given that red dot is about halfway between 12 and 13.

Draw a number line.Mark points on it on  as 1,2,3,.....12,13,...20.

Label 12 as point M and label 13 as N.

Mid point of MN=\frac{12+13}{2}

                         =25/2

                        =12.5

Mark 12.5 as T.

MT =NT

The Red dot is at point N at a distance of 12.5 units from the origin.



3 0
3 years ago
Solve for x: 2x - 2y = 10, y = - 5.5
il63 [147K]
2x-2y=10
Y=-5.5
Sub y into the equation and solve for x
2x-2(-5.5)=10
2x+11=10
2x=10-11
2x=-1
X=-1/2
Hope this helps!
3 0
3 years ago
If the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center a
Sedbober [7]

The distance from the center to where the foci are located exists 8 units.

<h3>How to determine the distance from the center?</h3>

The formula associated with the focus of an ellipse exists given as;

c² = a² − b²

Where c exists the distance from the focus to the center.

a exists the distance from the center to a vertex,

the major axis exists 10 units.

b exists the distance from the center to a co-vertex, the minor axis exists 6 units

c² = a² − b²

c² = 10² - 6²

c² = 100 - 36

c² = 64

c = \sqrt{64}

c = 8

Therefore, the distance from the center to where the foci are located exists 8 units.

To learn more about the Pythagorean theorem here:

brainly.com/question/654982

#SPJ4

3 0
1 year ago
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