I believe the best answer is B. Waking State
Answer:
U₂ = 20 J
KE₂ = 40 J
v= 12.64 m/s
Explanation:
Given that
H= 12 m
m = 0.5 kg
h= 4 m
The potential energy at position 1
U₁ = m g H
U₁ = 0.5 x 10 x 12 ( take g= 10 m/s²)
U₁ = 60 J
The potential energy at position 2
U₂ = m g h
U ₂= 0.5 x 10 x 4 ( take g= 10 m/s²)
U₂ = 20 J
The kinetic energy at position 1
KE= 0
The kinetic energy at position 2
KE= 1/2 m V²
From energy conservation
U₁+KE₁=U₂+KE₂
By putting the values
60 - 20 = KE₂
KE₂ = 40 J
lets take final velocity is v m/s
KE₂= 1/2 m v²
By putting the values
40 = 1/2 x 0.5 x v²
160 = v²
v= 12.64 m/s
I think 1 and 3 is absolutely right but im not sure about number 2.
I think the answer is 4 all of the above because as the vibration decrease automatically the kinetic energy decrease and the temperature is decrease because when the vibration of molecules decrease thats mean the substances is slightly become a solid and you can get a solid cube of liquid if you freeze them
The amount of work done during the kick is 200 Joules.
<h3>Formula for Work done </h3>
The formula for work done is Force× Distance
This is represented by fd
The force applied is 1,000 Newton
The displacement exerted by the force during kicking is 0.2meter
From this we can get the work done which is:
W= fd
= 1000N × 0.2m
= 200 Joules.
Read more about Work done here brainly.com/question/25191227
Answer:
6.02 s
Explanation:
We can write the position of the stock car as:
where
is the acceleration of the stock car.
The sport car instead starts its motion only 1.3 s afterwards, therefore its position at time t can be written as
where
is the acceleration of the sport car
(we can verify indeed that when t = 1.3 s, ).
The sport car reaches the stock car when the two positions are equal:
Rewriting the equation,
This is a second-order equation with two solutions:
t = 0.73 s
t = 6.02 s
We discard the first solution since we are only interested in the times > 1.3 s, therefore the sport car overcomes the stock car after
6.02 seconds.