Answer:
which pic...? there is no picture attached to your question
Answer:
force of attraction will be increased by 9
Explanation:
force of attraction is inversely proportional to square of distance
i.e F= 1/R²
F=1/3R²
F=1/9R
9×F= 9×1/9R
9F= 1/R
so force of attraction is 9 times
Answer:
the cannonball’s velocity parallel to the ground is 86.6m/S
Explanation:
Hello! To solve this problem remember that in a parabolic movement the horizontal component X of the velocity of the cannonball is constant while the vertical one varies with constant acceleration.
For this case we must draw the velocity triangle and find the component in X(see atached image).
V= Initial velocity=100M/S
V= Initial velocity=100M/S
Vx=cannonball’s velocity parallel to the ground
Solving for Vx
Vx=Vcos30
Vx=(100m/S)(cos30)=86.6m/s
the cannonball’s velocity parallel to the ground is 86.6m/S
Maximum height = 40 m.
Assume g = 9.8 m/s² and no air resistance.
Let V = vertical launch velocity.
At maximum height, the vertical velocity is zero.
Therefore
(V m/s)² - 2*(9.8 m/s²)*(40 m) = 0
V² = 784
V = 28 m/s
Let the pitcher throw the ball with velocity 28 m/s, at angle x relative to the horizontal.
The vertical component of the launch velocity is
28 sin(x),
and the horizontal component of the launch velocity is
28 cos(x)
The time, t, to reach maximum height is
28 sin(x)/9.8 = 2.8571 sin(x) s.
The total time of flight is
2t = 5.7142 sin(x) s
The horizontal distance traveled is
d = (28 cos(x) m/s)*(5.7142 sin(x) s)
= 160 sin(x) cos(x) m
Because sin(2x) = 2 sin(x) cos(x), therefore
d = 80 sin(2x)
d is maximum when 2x = 90° => x = 45°.
Therefore the maximum horizontal distance is 80 m.
Answer: 80 m