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arlik [135]
3 years ago
14

Find the measure of angle U

Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

30

Step-by-step explanation:

since angle S is supplementary you subtract 110 from 180 which is 70 and a whole triangle is 180 degrees you subtract 80 and 70 from 180 and you get 30

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The answer is x=8 or x=-13
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It is not B so plz help me
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The picture is blocked out D:

Step-by-step explanation:

6 0
3 years ago
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Find the difference quotient f(x)−(3)−3 when ()=1+4−5^2. Simplify the expression fully as if you were going to compute the limit
Naddik [55]

The difference quotient of the expression will be 4.

<h3>How to find the quotient?</h3>

f(x) = 5 + 5x + 4x²

f(3) = 5 + 5(3) + 4(3)³

= 56

Now [f(x) - f(3)]/(x - 3) will be:

= (4x² + 5x + 5 - 56)/(x - 3)

= (4x² + 5x - 51)/(x - 3)

= (4x² + 17x - 12x - 5)/(x - 3)

= (4x + 17)(x - 3)/(x - 3)

= 4x + 17

The difference quotient will be:

g(x + h) = 4(x + h) + 17

= [g(x + h) - g(x)]/h

= (4x + 4h + 17 - 4x - 17)/h

= 4h/h

= 4

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brainly.com/question/673545

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6 0
2 years ago
Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

  • a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

  • b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

  • c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

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8 0
2 years ago
The table shows the height of a softball that Hallie threw in the air. Is the relationship shown linear? Why or why not?
andrew11 [14]

Answer:

Not a linear relationship

Step-by-step explanation:

Given

The attached table

Required

Linear or not

To do this, we simply calculate the slope of the table at different intervals.

Slope (m) is calculated as:

m = \frac{y_2 - y_1}{x_2 - x_1}

Let:

(x_1,y_1) = (0,0)

(x_2,y_2) = (0.5,7.2)

So, the slope is:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{7.2 - 0}{0.5-0}

m = \frac{7.2}{0.5}

m = 14.4

Let:

Let:

(x_1,y_1) = (1,10.7)

(x_2,y_2) = (2,12.2)

So, the slope is:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{12.2 - 10.7}{2 - 1}

m = \frac{1.5}{1}

m = 1.5\\

See that the calculated slopes are not equal.

Hence, it is not linear

3 0
3 years ago
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